下面的SQL哪些有可能经过两个阶段（只经过一次shuffle）就计算出结果：（ ） A: SELECT key1, key2, SUM(value1) FROM (SELECT key1, key2, COUNT(*) FROM dual GROUP BY key1, key2) t1 GROUP BY key2, key1; B: SELECT a.key1, a.key2 FROM table1 a JOIN table2 b ON a.key1 = b.key; C: SELECT *, ROW_NUMBER() OVER(PARTITION BY key ORDER BY value1, value 2) id1, ROW_NUMBER() OVER(PARTITION BY key ORDER BY value1) id2 FROM dual;

Planning in advance is the key to 2) .

Four keys to getting hired are begun in different ways stylistically. Key 1 starts with a ____.Key 2 starts with a ___. Key 3 starts with a ____. Key4 starts with a ____.

How many key comparisons are needed in searching for key value 38（） A: 1 B: 2 C: 3 D: 4

代码填空【使用递归实现二分查找】 int binarySearch(int a[], int key, int low, int high) { if (low > high) return -1; int mid; mid = (low + high) / 2; if (key == a[mid]) return mid; else if (key < a[mid]) return ________(1)__________; else return ________(2)______________; }

1. 已知列表对象x=&#91;‘11’,’2’,’3’&#93;,则表达式max(x,key=len)的值为: ( )说明：key参数，参照sort函数的用法。 A: '11' B: '2' C: '3' D: 2

According to the main area of pixels in the histogram, the tone can be divided into A: Low key, high key, middle key B: Hard tone, soft tone C: Long key, short key D: Long key, middle key, short key

HashMap中的put()方法参数是() A: put(value,key) B: put(key,key) C: put(key,value) D: put(key,key)

关键码key实际存放的位置是： A: key B: key - 1 C: hash(key) D: hash(hash(key))

‌What should be put in Section 2?‌ A: details B: key words C: summary D: recording