【多选题】下 列语句中,()正确完成了整型变量的声明和赋值。 A. int count, count =0; B. int count = 0; C. count = 0; D. int count1 = 0, count2=l ;

下列语句中，哪个正确完成整形变量的声明和赋值 A: int conut,count=0; B: int count=0; C: count=0; D: int count1=0,count2=1;

查询选修了2门课程以上的学生学号（） A: select sid,count(*) from sc group by sid having count(*)>=2 B: select sid,count(*) from sc group by sid where count(*)>=2 C: select sid,count(*) from sc where count(*)>=2 group by sid D: select sid,count(*) from sc group by cid having count(*)>=2

select count(*) from 表名 having count(*)>;2

(Short-answer Question)What transitional states are possible when a 4-bit asynchronous binary counter changes from (a) count 2 to count 3 (b) count 3 to count 4 (c) count 1010 to count 1110 (d) count 15 to count 0

若COUNT(A1:A3)=2,则COUNT(A1:A3,3)=5

执行下述代码: count = 5 def print_num(): count = 2 count += 1 print(count) 当调用print_num()函数时,输出结果为( )

以下程序段的输出结果是（ ）。[img=294x478]17e43bcb95a3936.png[/img] A: count= 1 B: count=2 C: count=3 D: count=4

阅读以下程序public class Count{static int count;int number;public Count(){count = count + 1;number = count;}}class Test{public static void Main(){Count a = new Count();Count b = new Count();Count c = new Count();}}程序运行后，对象a的count值是（） A: 0 B: 1 C: 2 D: 3

1.从严格意义上讲，下列的程序表示的是一个算法吗？为什么？Count = 0while(Count != 5):Count = Count + 2