下列选项中,JavaScript变量名称不合法的是( ) A: number_1 B: 2number C: sum D: number$f
下列选项中,JavaScript变量名称不合法的是( ) A: number_1 B: 2number C: sum D: number$f
下列表达式可以作为判断一个整数number为奇数的是() A: number // 2 == 1 B: number // 2 == 0 C: number % 2 == 1 D: number / 2 == 1
下列表达式可以作为判断一个整数number为奇数的是() A: number // 2 == 1 B: number // 2 == 0 C: number % 2 == 1 D: number / 2 == 1
以下程序的输出结果是___________。 number = 10 if number % 2 == 0: print(number, 'is even') elif number % 5 == 0: print(number, 'is multiple of 2')
以下程序的输出结果是___________。 number = 10 if number % 2 == 0: print(number, 'is even') elif number % 5 == 0: print(number, 'is multiple of 2')
int number_range=20;int number=2;boolean isprime=true;while(number<;number_range){isprime=true;for(int divlsor=2;divlsor<;=number/2;divlsor++){if(______){isprime=false;break;}}if(isprime){out.println(number+"<;br>;");}number++;}%>; A: divlsor%number==0 B: number%divlsor==0 C: divlsor/number==0 D: number/divlsor==0
int number_range=20;int number=2;boolean isprime=true;while(number<;number_range){isprime=true;for(int divlsor=2;divlsor<;=number/2;divlsor++){if(______){isprime=false;break;}}if(isprime){out.println(number+"<;br>;");}number++;}%>; A: divlsor%number==0 B: number%divlsor==0 C: divlsor/number==0 D: number/divlsor==0
The number of employees (2)
The number of employees (2)
中国大学MOOC: 以下程序的输出结果是?number = 30if number % 2 == 0: print(number, is even)elif number % 3 == 0: print(number, is multiple of 3)
中国大学MOOC: 以下程序的输出结果是?number = 30if number % 2 == 0: print(number, is even)elif number % 3 == 0: print(number, is multiple of 3)
2. Which bus will the woman take? A: Bus number 4 B: Bus number 6 C: Bus number 2 D: ...
2. Which bus will the woman take? A: Bus number 4 B: Bus number 6 C: Bus number 2 D: ...
The girl is working in the: (1) The room number the girl will rent: (2) The price to be paid is: (3) The girl’s phone number is: (4) 2()
The girl is working in the: (1) The room number the girl will rent: (2) The price to be paid is: (3) The girl’s phone number is: (4) 2()
Analyze the following code: Code 1: int number = 45; bool even; if (number % 2 == 0) even = true; else even = false; Code 2: int number = 45; bool even = (number % 2 == 0); A: Code 1 has compile errors. B: Code 2 has compile errors. C: Both Code 1 and Code 2 have compile errors. D: Both Code 1 and Code 2 are correct, but Code 2 is better.
Analyze the following code: Code 1: int number = 45; bool even; if (number % 2 == 0) even = true; else even = false; Code 2: int number = 45; bool even = (number % 2 == 0); A: Code 1 has compile errors. B: Code 2 has compile errors. C: Both Code 1 and Code 2 have compile errors. D: Both Code 1 and Code 2 are correct, but Code 2 is better.
假设 number 的输入是9。以下程序将显示什么?number = eval(input("Enter an integer: ")) isPrime = True for i in range(2, number): if number % i == 0: isPrime = False print("i is", i) if isPrime: print(number, "is prime") break else: print(number, "is not prime") A: i is 3 9 is prime B: i is 3 9 is not prime C: i is 2 9 is prime D: i is 2 9 is not prime
假设 number 的输入是9。以下程序将显示什么?number = eval(input("Enter an integer: ")) isPrime = True for i in range(2, number): if number % i == 0: isPrime = False print("i is", i) if isPrime: print(number, "is prime") break else: print(number, "is not prime") A: i is 3 9 is prime B: i is 3 9 is not prime C: i is 2 9 is prime D: i is 2 9 is not prime