(5)、 [单选题] （1分） A: It’s 3011575. B: It’s 3011474. C: It’s 3011574. D: It’s 3011754

若有定义char s[] = {“hello”};则sizeof(s)的大小为5。

n1 = { 'a':1, 'b':2 }n2 = n1n1['a'] = 5s = n1['a'] + n2['a']print(s)代码的结果是？ A: 5 B: 10 C: 6 D: 7

.部分分式展开法求F(S)逆拉氏变换‏L-1[F(s)] = L-1[F1(s)]+L-1[F2(s)]+…+L-1[Fn(s)]‏=( )‏

序列s =["seashell","gold","pink","brown","purple","tomato"],则print(len(s),min(s),max(s))结果为（） A: 6 seashell gold B: 5 pink brown C: 6 brown tomato D: 5 purple tomato

假设有如下定义语句：char s[]=”Hello”;则数组s的大小为5。

下面代码的输出结果是‪‬‪‬‪‬‪‬‪‬‮‬‪‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬s =["seashell","gold","pink","brown","purple","tomato"]print(len(s),min(s),max(s)) A: 6 seashell gold B: 5 purple tomato C: 5 pink brown D: 6 brown tomato

下面代码的输出结果是（ ）。‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‪‫s =["seashell","gold","pink","brown","purple","tomato"]print(len(s),min(s),max(s)) A: 5 pink brown B: 6 brown tomato C: 5 purple tomato D: 6 seashell gold

以下代码的输出结果是（ ）。s=[“seashell”,“gold”,“pink”,“brown”,“purple”,“tomato”]print(len(s),min(s),max(s)) A: 5 purple tomato B: 5 pink brown C: 6 seashell gold D: 6 brown tomato

执行下列代码段后，s的值为________。 int a&#91;&#93; = {5, 3, 7, 2, 1, 5, 3, 10}; int k, s = 0; for(k = 0; k < 8; k += 2) s += a&#91;k&#93;;