• 2022-06-01 问题

    能用来判断变量x“在2013到2016之间(含2013和2016)”的表达式是: A: ( 2013 B: ( 2013 C: ( x >= 2013 ) && ( x D: ( x = 2013 ) E: ( x >= 2013 ) || ( x F: ( x >= 2013 ) | ( x

    能用来判断变量x“在2013到2016之间(含2013和2016)”的表达式是: A: ( 2013 B: ( 2013 C: ( x >= 2013 ) && ( x D: ( x = 2013 ) E: ( x >= 2013 ) || ( x F: ( x >= 2013 ) | ( x

  • 2022-06-19 问题

    设凼数f(x)=ax(a>0,a≠1),如果f(x1+x2+…+x2013)=8,那么f(2x1)•f(2x2)…f(2x2013)的值等于(  )A.32B.64C.16D.8

    设凼数f(x)=ax(a>0,a≠1),如果f(x1+x2+…+x2013)=8,那么f(2x1)•f(2x2)…f(2x2013)的值等于(  )A.32B.64C.16D.8

  • 2022-06-12 问题

    计算:(-2 )2012×()2013=       .

    计算:(-2 )2012×()2013=       .

  • 2022-05-27 问题

    就坐时占椅面的()左右,于礼最为合适。 A: 2013/1/2 B: 2013/2/3 C: 2013/3/4 D: 整个椅面

    就坐时占椅面的()左右,于礼最为合适。 A: 2013/1/2 B: 2013/2/3 C: 2013/3/4 D: 整个椅面

  • 2022-06-12 问题

    2011²+2013²-2分之2012²

    2011²+2013²-2分之2012²

  • 2021-04-14 问题

    (2013)若f(-x)=-f(x)(-221e0,f″(x)<0,则f(x)在(0,+221e)内是:()

    (2013)若f(-x)=-f(x)(-221e0,f″(x)<0,则f(x)在(0,+221e)内是:()

  • 2022-06-09 问题

    设\(z = \int_ { { x^2}}^y { { e^t}\sin t} dt\),则\({z_{xx}=}\) A: \(2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\sin {x^2} + 2{x^2}\cos {x^2}} \right]\) B: \( - 2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\sin {x^2} - 2{x^2}\cos {x^2}} \right]\) C: \( - 2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\sin {x^2} + 2{x^2}\cos {x^2}} \right]\) D: \( - 2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\cos {x^2} + 2{x^2}\sin {x^2}} \right]\)

    设\(z = \int_ { { x^2}}^y { { e^t}\sin t} dt\),则\({z_{xx}=}\) A: \(2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\sin {x^2} + 2{x^2}\cos {x^2}} \right]\) B: \( - 2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\sin {x^2} - 2{x^2}\cos {x^2}} \right]\) C: \( - 2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\sin {x^2} + 2{x^2}\cos {x^2}} \right]\) D: \( - 2{e^ { { x^2}}}\left[ {\left( {1 + 2{x^2}} \right)\cos {x^2} + 2{x^2}\sin {x^2}} \right]\)

  • 2022-05-31 问题

    数学式 A: (e^(2*x)*Log(x)+x^2)/Sqr(Abs(Sinx^2-Cos2x)) B: (Exp(2*x)*Log(x)+x^2)/Sqr(Abs(Sin(x^2)-Cos(x)^2)) C: (Exp(2*x)*Ln(x)+x^2)/Sqr(Abs(Sin(x^2)-Cos(x)^2)) D: (e^(2*x)*Log(x)+x^2)/Sqr(Abs(Sin(x)^2-Cos(x)^2))

    数学式 A: (e^(2*x)*Log(x)+x^2)/Sqr(Abs(Sinx^2-Cos2x)) B: (Exp(2*x)*Log(x)+x^2)/Sqr(Abs(Sin(x^2)-Cos(x)^2)) C: (Exp(2*x)*Ln(x)+x^2)/Sqr(Abs(Sin(x^2)-Cos(x)^2)) D: (e^(2*x)*Log(x)+x^2)/Sqr(Abs(Sin(x)^2-Cos(x)^2))

  • 2022-06-19 问题

    与数学关系式[img=114x22]1803bce8722f322.png[/img]等价的C语言关系表达式是? A: x < -2 && x > 2 B: x < -2 || x > 2 C: -2 < x < 2 D: !(-2 <= x <=2) E: !(-2 <=x && x <= 2) F: x < -2, x > 2

    与数学关系式[img=114x22]1803bce8722f322.png[/img]等价的C语言关系表达式是? A: x < -2 && x > 2 B: x < -2 || x > 2 C: -2 < x < 2 D: !(-2 <= x <=2) E: !(-2 <=x && x <= 2) F: x < -2, x > 2

  • 2022-06-01 问题

    求微分方程[img=101x35]17da5f15503f795.png[/img] 的通解,实验命令为(). A: dsolve(Dy+2*x*y=x*exp(-x^2))ans=C1*exp(-x^2) + (x^2*exp(-x^2))/2 B: dsolve('Dy+2*x*y=x*exp(-x^2)','x')ans=C1*exp(-x^2) + (x^2*exp(-x^2))/2 C: dsolve('Dy+2*x*y=x*exp(-x^2)')ans=C1*exp(-x^2) + (x^2*exp(-x^2))/2

    求微分方程[img=101x35]17da5f15503f795.png[/img] 的通解,实验命令为(). A: dsolve(Dy+2*x*y=x*exp(-x^2))ans=C1*exp(-x^2) + (x^2*exp(-x^2))/2 B: dsolve('Dy+2*x*y=x*exp(-x^2)','x')ans=C1*exp(-x^2) + (x^2*exp(-x^2))/2 C: dsolve('Dy+2*x*y=x*exp(-x^2)')ans=C1*exp(-x^2) + (x^2*exp(-x^2))/2

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