• 2022-05-29 问题

    如图所示电路,已知ε1=5 V,ε2=3 V,R内1=R内2=1 Ω,R1=R2=R3=2 Ω,则Uab=[img=218x121]17e0aaba219d507.jpg[/img] A: 5 V B: 2 V C: -1 V D: 1 V E: -2 V

    如图所示电路,已知ε1=5 V,ε2=3 V,R内1=R内2=1 Ω,R1=R2=R3=2 Ω,则Uab=[img=218x121]17e0aaba219d507.jpg[/img] A: 5 V B: 2 V C: -1 V D: 1 V E: -2 V

  • 2021-04-14 问题

    【单选题】底面半径为 R高为R的圆锥体积为V 1 ,半径为 R的半球体积是V 2 ,底面半径为 R高为R的圆柱体积为V 3 ,则有() A. V 1 :V 2 :V 3 =1:4:9 B. V 1 :V 2 :V 3 =1:2:3 C. V 1 :V 2 :V 3 =1:3:5 D. A.V 2 2 =V 1 V 3

    【单选题】底面半径为 R高为R的圆锥体积为V 1 ,半径为 R的半球体积是V 2 ,底面半径为 R高为R的圆柱体积为V 3 ,则有() A. V 1 :V 2 :V 3 =1:4:9 B. V 1 :V 2 :V 3 =1:2:3 C. V 1 :V 2 :V 3 =1:3:5 D. A.V 2 2 =V 1 V 3

  • 2022-06-06 问题

    右心室肥大的心电图可表现为() A: R<sub>V1</sub>>1.0mR<sub>V1</sub>+S<sub>V5</sub>>1.2mV B: V<sub>3</sub>、V<sub>4</sub>导联呈RS型,R/S接近于1 C: V<sub>5</sub>、V<sub>6</sub>导联以R波为主,R/S>1,R<sub>V5</sub><2.5mV D: V<sub>1</sub>至V<sub>5</sub>,R波逐渐增大,而S波逐渐变小 E: R<sub>V5</sub>>2.5mV,V<sub>1</sub>或R<sub>V5</sub>+S<sub>V1</sub>>3.5~4.0mV

    右心室肥大的心电图可表现为() A: R<sub>V1</sub>>1.0mR<sub>V1</sub>+S<sub>V5</sub>>1.2mV B: V<sub>3</sub>、V<sub>4</sub>导联呈RS型,R/S接近于1 C: V<sub>5</sub>、V<sub>6</sub>导联以R波为主,R/S>1,R<sub>V5</sub><2.5mV D: V<sub>1</sub>至V<sub>5</sub>,R波逐渐增大,而S波逐渐变小 E: R<sub>V5</sub>>2.5mV,V<sub>1</sub>或R<sub>V5</sub>+S<sub>V1</sub>>3.5~4.0mV

  • 2022-06-14 问题

    RLC串联电路中,已知R=XL=XC=5Ω,=1∠0°A,则电路的端电压为()。 A: 1∠0°×(5+j10)V B: 5∠0°V C: 15∠90°V D: 15∠0°V

    RLC串联电路中,已知R=XL=XC=5Ω,=1∠0°A,则电路的端电压为()。 A: 1∠0°×(5+j10)V B: 5∠0°V C: 15∠90°V D: 15∠0°V

  • 2022-10-25 问题

    欧姆定律,简易公式为() A: I=V/R B: V=I/R C: R=IV D: I=R/V

    欧姆定律,简易公式为() A: I=V/R B: V=I/R C: R=IV D: I=R/V

  • 2022-06-28 问题

    用矢量法表示定轴转动刚体内任一点的加速度为() A: v=r×ω B: v=r•ω C: v=ω×r D: v=-ω•r

    用矢量法表示定轴转动刚体内任一点的加速度为() A: v=r×ω B: v=r•ω C: v=ω×r D: v=-ω•r

  • 2022-06-09 问题

    静态工作点的值IBQ≈()。 A: V CC/R C B: V CC/R E C: V CC/R B D: V CC/R L

    静态工作点的值IBQ≈()。 A: V CC/R C B: V CC/R E C: V CC/R B D: V CC/R L

  • 2022-05-28 问题

    一物体做半径为r的圆周运动,其线速度v与角速度ω的关系为 A: v=rω B: v=r/ω C: v=ω D: v=r2ω

    一物体做半径为r的圆周运动,其线速度v与角速度ω的关系为 A: v=rω B: v=r/ω C: v=ω D: v=r2ω

  • 2022-06-07 问题

    A signal s(t)=3cos(20pt) (V) is quantized by a uniform quantizer, the step size of the quantizer is 0.1(V), then the minimal number of quantization level is L , the number of bits per sample is at least R , and the variance of the quantization error is T ([img=22x22]1803a28ec2869ac.png[/img]). A: L=60, R=5, T=0.000833 B: L=30, R=5, T=0.000833 C: L=60, R=5, T=0.001667 D: L=60, R=6, T=0.000833

    A signal s(t)=3cos(20pt) (V) is quantized by a uniform quantizer, the step size of the quantizer is 0.1(V), then the minimal number of quantization level is L , the number of bits per sample is at least R , and the variance of the quantization error is T ([img=22x22]1803a28ec2869ac.png[/img]). A: L=60, R=5, T=0.000833 B: L=30, R=5, T=0.000833 C: L=60, R=5, T=0.001667 D: L=60, R=6, T=0.000833

  • 2022-06-07 问题

    ‏A signal s(t)=3cos(20pt) (V) is quantized by a uniform quantizer, the step size of the quantizer is 0.1(V), then the minimal number of quantization level is L , the number of bits per sample is at least R , and the variance of the quantization error is T ([img=22x22]1802e166a76be1c.png[/img]).‎ A: L=60, R=5, T=0.000833 B: L=30, R=5, T=0.000833 C: L=60, R=5, T=0.001667 D: L=60, R=6, T=0.000833

    ‏A signal s(t)=3cos(20pt) (V) is quantized by a uniform quantizer, the step size of the quantizer is 0.1(V), then the minimal number of quantization level is L , the number of bits per sample is at least R , and the variance of the quantization error is T ([img=22x22]1802e166a76be1c.png[/img]).‎ A: L=60, R=5, T=0.000833 B: L=30, R=5, T=0.000833 C: L=60, R=5, T=0.001667 D: L=60, R=6, T=0.000833

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