设X ~ N(2, 9)则Y = (X – 2 )/9 ~ N(0, 1).

中国大学MOOC: 设X~N(2, 9)则Y= (X– 2 )/9 ~N(0,1).

与数学式子[img=43x34]17e0acb62c85ed0.jpg[/img]对应的C语言表达式是 A: 9*x^n/(2*x-1) B: 9*x**n/(2*x-1) C: 9*pow(x,n)*(1/(2*x-1)) D: 9*pow(n,x)/(2*x-1)

中国大学MOOC: 设X~N(2, 9)则Y= (X– 2 )/9 ~N(0, 1).

设X ~ N(2, 9)则Y = (X – 2 )/9 ~ N(0, 1). A: 正确 B: 错误

以4，9，1为为插值节点，求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)

以下方程在空间中不是柱面的是（ ）。 A: \( {x^2} + {y^2} + {z^2} = 9 \) B: \( y = 4{x^2} \) C: \( {x^2} + {y^2} = 9 \) D: \( {x^2} - {y^2} = 3z \)

缓和曲线采用切线支距法计算坐标的公式为（） A: x=ι-ι4/（40R2I02）+ι9/（3456R4I04）… B: x=ι-ι5/（40R2I02）+ι9/（3456R4I04）… C: x=ι-ι3/（40R2I02）+ι9/（3456R4I04）… D: x=ι-ι2/（40R2I02）+ι9/（3456R4I04）…

已知函数定义def demo(a=1,**b):return b则demo(2,x=7,y=8,z=9)的返回值是什么? A: 2 B: (x:7,y:8,z:9) C: (7, 8, 9) D: {'x':7, 'y':8, 'z':9}

函数的定义域是( ) A: {(x，|2＜x2+y2＜3} B: {(x，|4＜x2+y2＜9} C: {(x，|4＜x2+y2≤9} D: {(x，|22+y2≤3}