编写一个函数实现两个数的交换,函数原型为:voidSwap(int*a,int*b)。

中国大学MOOC: 以下代码的输出是 ：voidswap(int*pa,int*pb){intpt;pt=*pa,*pa=*pb,*pb=*pa;}intmain(void){intx=1,y=2;f(＆x,＆y);printf("%d%d",x,y);}

编写变量交换函数,交换两个指针变量所指向的两个变量的值。即voidswap(int*a,int*b)

以下程序的运行结果是voidswap1(intx[],inty[]){intt;t=x[0];x[0]=y[0];y[0]=t;}voidswap2(int*x,int*y){intt;t=*x;*x=*y;*y=t;}main(){inta[2]={3,5},b[2]={3,5};swap1(a,a+1);swap2(&b[0],&b[1]);printf("%d%d%d%d\n",a[0],a[1],b[0],b[1]);}

已知swap函数模板的定义如下： template[typenameT] voidswap(T&var1,T&var2) { Ttemp=var1; var1=var2; var2=temp; } 可使用以下哪种方式调用swap？___________ A: A.intv1=1;intv2=2;swap(v1,v2); B: B.swap(1,2); C: C.intv1=1;intv2=2;swap(&v1,&v2); D: D.intv1=1;doublev2=2;swap(v1,v2);

以下程序的运行结果是______。voidswap(int**r,int**s){int*t;t=*r;*r=*s;*s=t;}voidmain(){inta=1,b=2,*p,*q;p=&a;q=&b;swap(&p,&q);printf("%d,%d\n",*p,*q);}

下列函数的功能为。voidSwap(int*p1,int*p2){intp3;p3=*p1;*p1=*p2;*p2=p3;} A: 交换*p1和*p2的值 B: 交换*p1和*p2的地址 C: 正确，但无法改变*p1和*p2的值 D: 可能造成系统故障

写出下列程序运行结果 #include “stdio.h” void swap(int *px , int *py ); void main() { int a,b; a=5; b=10; printf(“ before swap a=%d, b=%d ”,a,b); swap(&a,&b); printf(“after swap a=%d, b=%d ”,a,b); } voidswap(int *px , int *py ) { int temp; temp=*px; *px=* py; *py=temp; printf(“ in swap x=%d,y=%d ”,*px, *py); }

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1