表达式:"123"+456"123"&456的结果分别为() A: "123456"和579 B: 579和"123456" C: "579"和123456 D: 579和"579"
表达式:"123"+456"123"&456的结果分别为() A: "123456"和579 B: 579和"123456" C: "579"和123456 D: 579和"579"
579、呕血
579、呕血
表达式‘123’+‘456’的结果是( ) A: '579' B: 579 C: '123456' D: '123'
表达式‘123’+‘456’的结果是( ) A: '579' B: 579 C: '123456' D: '123'
表达式 ’123’+’456’ 的结果是 A: '579' B: 579 C: '123456' D: '234567'
表达式 ’123’+’456’ 的结果是 A: '579' B: 579 C: '123456' D: '234567'
语句printcast(123asnchar(5))+’456’的结果是()。 A: ’579’ B: 579 C: ’123456’ D: ’12345’
语句printcast(123asnchar(5))+’456’的结果是()。 A: ’579’ B: 579 C: ’123456’ D: ’12345’
已知 x = '123' 和 y = '456',那么表达式 x + y 的值为_________。(1.0) A: 123456 B: '123456' C: '579' D: 579
已知 x = '123' 和 y = '456',那么表达式 x + y 的值为_________。(1.0) A: 123456 B: '123456' C: '579' D: 579
表达式:"123"+456的值为579。()
表达式:"123"+456的值为579。()
Word中插入数学公式的方法是()。 A: "插入"→"形状"→"公式" B: "开发工具"→"公式" C: "插入"→"公式"→"插入新公式" D: "引用"→"插入"→"公式"
Word中插入数学公式的方法是()。 A: "插入"→"形状"→"公式" B: "开发工具"→"公式" C: "插入"→"公式"→"插入新公式" D: "引用"→"插入"→"公式"
定义并初始化一个用于存放我们国家的四个直辖市的数组cityName,四个直辖市为:北京,上海,天津,重庆. 正确的是_________ A: String[] cityName=new String[4]{"北京","上海","天津","重庆"}; B: String[] cityName=new String[]{"北京","上海","天津","重庆"}; C: String[] cityName={"北京","上海","天津","重庆"}; D: String cityName = new String[4] { "北京", "上海", "天津", "重庆" };
定义并初始化一个用于存放我们国家的四个直辖市的数组cityName,四个直辖市为:北京,上海,天津,重庆. 正确的是_________ A: String[] cityName=new String[4]{"北京","上海","天津","重庆"}; B: String[] cityName=new String[]{"北京","上海","天津","重庆"}; C: String[] cityName={"北京","上海","天津","重庆"}; D: String cityName = new String[4] { "北京", "上海", "天津", "重庆" };
已知有一个名为names的空列表,如何向其中添加old_driver,rain,jack,shanshan,peiqi,black_girl 元素? A: names.append("old_driver","rain","jack","shanshan","peiqi","black_girl") B: names.extend("old_driver","rain","jack","shanshan","peiqi","black_girl") C: names.insert("old_driver","rain","jack","shanshan","peiqi","black_girl") D: names.extend(["old_driver","rain","jack","shanshan","peiqi","black_girl"])
已知有一个名为names的空列表,如何向其中添加old_driver,rain,jack,shanshan,peiqi,black_girl 元素? A: names.append("old_driver","rain","jack","shanshan","peiqi","black_girl") B: names.extend("old_driver","rain","jack","shanshan","peiqi","black_girl") C: names.insert("old_driver","rain","jack","shanshan","peiqi","black_girl") D: names.extend(["old_driver","rain","jack","shanshan","peiqi","black_girl"])