下面代码的输出结果是()。 <?php $score=87; if($score>=90 && $score<=100){$grade="优秀";} if($score>=80){$grade="良好";} if($score>=70){$grade="一般";} if($score>=60){$grade="及格";} else{$grade="不及格";} echo $grade; ?>

以下参数传递正确的是： A: def score(mid_score, end_score): ……score(88, 79) B: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(88, 79) C: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(end_score = 79, mid_score = 88) D: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(mid_score = 88, end_score = 79,0.5)

【单选题】txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。txt ,图片,Word。 A. 1 B. txt ,图片，Word。 C. txt ,图片，Word。

There are ________students playing basketball in the room. A: score of B: scores of C: two score D: two score of

若有定义int score&#91;10&#93;;，则对score数组中的元素的正确引用是（ ） A: score[10] B: score[6.0] C: score[0] D: score(7)

从学生成绩表SC中查询平均成绩大于60分的同学的学号和平均成绩的正确语句为： A: selectsno,avg(score)assscorefromscgroupbysnohavingavg(score)>60 B: selectsno,avg(score)assscorefromscgroupbysnowhereavg(score)>60 C: selectsno,avg(score)assscorefromscwhereavg(score)>60 D: selectsno,avg(score)assscorefromschavingavg(score)>60

查询成绩在60-80之间的学生信息，正确的语句是？ A: db.students.find({"score":{$gte:60,$lte:80}}) B: db.students.find({"score":{$gte:80},{"score":{$lte:60}}}) C: db.students.find({"score":{$gte:60},{"score":{$te:80}}}) D: db.students.find({"score":{$gt:80},{"score":{$lt:60}}})

下列程序片段用于产生成绩等第，已定义score%和mark$分别表示成绩和等第。即60分（含）以上及格、75分（含）以上良好、90分（含）以上优秀，能获得预期结果的是______。 A: If score>=90 Then Mark="优秀" ElseIf score>=75 Then Mark="良好" ElseIf score>=60 Then Mark="及格" End If B: If score>=60 Then Mark="及格" ElseIf score>=75 Then Mark="良好" ElseIf score>=90 Then Mark="优秀" C: If score>=90 Then Mark="优秀"If score>=75 Then Mark="良好"If score>=60 Then Mark="及格" D: If score>=60 Then Mark="及格" ElseIf score>=75 Then Mark="良好"ElseIf score>=90 Then Mark="优秀" End If

low marks A: a bad score B: a good score

A．SELECT Cno, AVG(Score) FROM SCS GROUP BY Score ORDER BY 2, Cno Desc B．SELECT Cno, AVG(Score) FROM SCS GROUP BY Cno ORDER BY 2, Cno Desc C．SELECT Cno, AVG(Score) FROM SCS WHERE Cno, Desc GROUP BY Score D．SELECT Cno, AVG(Score) FROM SCS GROUP BY, AVG(Score) ORDER BY, Cno Desc