原油粘度单位是()。 A: Akg/m3 B: BMPa C: CMPa-1 D: DmPa•s
原油粘度单位是()。 A: Akg/m3 B: BMPa C: CMPa-1 D: DmPa•s
下列哪项不是我国法定的压力单位:() A: APa B: BN/㎡ C: CMPa D: D帕斯卡
下列哪项不是我国法定的压力单位:() A: APa B: BN/㎡ C: CMPa D: D帕斯卡
事件CTR = PRD的含义是( )。 A: TBCTR = TBPRD B: TBCTR = 0 C: TBCTR = CMPA D: TBCTR = CMPB
事件CTR = PRD的含义是( )。 A: TBCTR = TBPRD B: TBCTR = 0 C: TBCTR = CMPA D: TBCTR = CMPB
工程大气压的单位是()。 A: Akgf/cm<sup>2</sup> B: Bkgf/m<sup>2</sup> C: CMPa D: DPa
工程大气压的单位是()。 A: Akgf/cm<sup>2</sup> B: Bkgf/m<sup>2</sup> C: CMPa D: DPa
在如下方波输出控制程序中,占空比计算公式为()。[br][/br]void PWM_Init()[br][/br]{ [br][/br]PWM0->TBPRD = 400; [br][/br]PWM1->TBCTL = 0;[br][/br]PWM1->TBCTL_b.HSPCLKDIV = 1;[br][/br]PWM1->TBCTL_b.CLKDIV = 4; [br][/br]PWM1->TBCTL_b.PRDLD = 1; [br][/br]PWM0->TBCTL_b.CTRMODE = 2; [br][/br]PWM0->AQCTLA_b.CAU = 1;[br][/br]PWM0->AQCTLA_b.CAD = 2;[br][/br]PWM0->CMPA = 200; [br][/br]PWM_START; [br][/br]} A: PWM0->AQCTLA_b.CAU /PWM0->AQCTLA_b.CAD=50% B: PWM0->TBCTL_b.CTRMODE/PWM1->TBCTL_b.CLKDIV=50% C: PWM1->TBCTL_b.HSPCLKDIV/PWM1->TBCTL_b.CLKDIV=25% D: PWM0->CMPA/PWM0->TBPRD=50%
在如下方波输出控制程序中,占空比计算公式为()。[br][/br]void PWM_Init()[br][/br]{ [br][/br]PWM0->TBPRD = 400; [br][/br]PWM1->TBCTL = 0;[br][/br]PWM1->TBCTL_b.HSPCLKDIV = 1;[br][/br]PWM1->TBCTL_b.CLKDIV = 4; [br][/br]PWM1->TBCTL_b.PRDLD = 1; [br][/br]PWM0->TBCTL_b.CTRMODE = 2; [br][/br]PWM0->AQCTLA_b.CAU = 1;[br][/br]PWM0->AQCTLA_b.CAD = 2;[br][/br]PWM0->CMPA = 200; [br][/br]PWM_START; [br][/br]} A: PWM0->AQCTLA_b.CAU /PWM0->AQCTLA_b.CAD=50% B: PWM0->TBCTL_b.CTRMODE/PWM1->TBCTL_b.CLKDIV=50% C: PWM1->TBCTL_b.HSPCLKDIV/PWM1->TBCTL_b.CLKDIV=25% D: PWM0->CMPA/PWM0->TBPRD=50%
AAA式的三段论,它的大前提是MAP,小前提是SAM,那么它的结论是() A: ASMP B: BSAP C: CMPA D: DSPA
AAA式的三段论,它的大前提是MAP,小前提是SAM,那么它的结论是() A: ASMP B: BSAP C: CMPA D: DSPA
可用于手性药物对映体拆分的方法 A: CDR法 B: LC- MS- MS法 C: UPLC法 D: CSP法 E: CMPA法
可用于手性药物对映体拆分的方法 A: CDR法 B: LC- MS- MS法 C: UPLC法 D: CSP法 E: CMPA法
在TMS320F28335中,若ePWM模块中的比较功能CC子模块可以产生以下______事件。( ) A: CTR=CMPA B: CTR=zero C: CTR=CMPB D: CTR=PRD
在TMS320F28335中,若ePWM模块中的比较功能CC子模块可以产生以下______事件。( ) A: CTR=CMPA B: CTR=zero C: CTR=CMPB D: CTR=PRD
for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常
for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常
【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1
【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1