• 2022-06-07 问题

    4.There are no banks in Chinatown in London.

    4.There are no banks in Chinatown in London.

  • 2022-06-15 问题

    4.There was no credible evidence against him.

    4.There was no credible evidence against him.

  • 2021-04-14 问题

    4.There is now a growing   of the importance of recycling among the residents in ourneighborhood.

    4.There is now a growing   of the importance of recycling among the residents in ourneighborhood.

  • 2022-06-07 问题

    中国大学MOOC: 4.There is a wide variety of ethnic food. These dishes are often cooked in such a way as to look and taste exactly like meat and fish.

    中国大学MOOC: 4.There is a wide variety of ethnic food. These dishes are often cooked in such a way as to look and taste exactly like meat and fish.

  • 2021-04-14 问题

    在所给的算式中,填上+、-、×、÷和( ),使得下面算式成立。(1)4 4 4 4=1(2)4 4 4 4=1(3)4 4 4 4=2(4)4 4 4 4=3[8分]

    在所给的算式中,填上+、-、×、÷和( ),使得下面算式成立。(1)4 4 4 4=1(2)4 4 4 4=1(3)4 4 4 4=2(4)4 4 4 4=3[8分]

  • 2021-04-14 问题

    数列-4, 4, -4, 4, -4…….

    数列-4, 4, -4, 4, -4…….

  • 2021-04-14 问题

    表达式4^4\4*4*4/4 Mod 4的值是

    表达式4^4\4*4*4/4 Mod 4的值是

  • 2021-04-14 问题

    【多选题】在下面 4 个 4 中间填上适当的运算符号和小括号使算式成立。 4 4 4 4=2 A. 4÷ 4 +4÷ 4=2 B. 4× 4÷ ( 4+ 4 ) =2 C. 4+ 4 +4 ×4=2 D. 4- ( 4 +4 ) ÷4=2 答

    【多选题】在下面 4 个 4 中间填上适当的运算符号和小括号使算式成立。 4 4 4 4=2 A. 4÷ 4 +4÷ 4=2 B. 4× 4÷ ( 4+ 4 ) =2 C. 4+ 4 +4 ×4=2 D. 4- ( 4 +4 ) ÷4=2 答

  • 2021-04-14 问题

    单音听辨。十个音为一组,含有变化音升4 [音频]/module/audioplay.html?objectid=525dda751efa2c644ef98798529599a7: *4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |1 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |2 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 6 |2 |*4 |

    单音听辨。十个音为一组,含有变化音升4 [音频]/module/audioplay.html?objectid=525dda751efa2c644ef98798529599a7: *4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |1 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 4 |2 |*4 ||*4 | 7 |升4 |-5 | 4 | 升4 |*4 | 6 |2 |*4 |

  • 2022-07-29 问题

    下列哪个是《圆舞曲》的乐段结构? A: a(4)+b(4)+a(4)+c(4) B: a(4)+b(4)+a(4)a1(4) C: a(4)+b(4)+a1(4)+c(4)

    下列哪个是《圆舞曲》的乐段结构? A: a(4)+b(4)+a(4)+c(4) B: a(4)+b(4)+a(4)a1(4) C: a(4)+b(4)+a1(4)+c(4)

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