图中ET段在侧面上投影应为虚线/sqp/img?f=0c1cca171831f76bf2102f2267474046.files%2Fimage007.png
举一反三
- 图中FS段在侧面上投影应为虚线/sqp/img?f=0c1cca171831f76bf2102f2267474046.files%2Fimage006.png
- 图中SB段在水平面上投影应为虚线/sqp/img?f=0c1cca171831f76bf2102f2267474046.files%2Fimage008.png
- 设,则在点均可微是在 点可微的 /sqp/img?f=399564cbae5b180fa94e94b3faa5fe8f.files%2Fimage003.png/sqp/img?f=399564cbae5b180fa94e94b3faa5fe8f.files/image004.png/sqp/img?f=399564cbae5b180fa94e94b3faa5fe8f.files%2Fimage005.png/sqp/img?f=399564cbae5b180fa94e94b3faa5fe8f.files/image006.png/sqp/img?f=399564cbae5b180fa94e94b3faa5fe8f.files%2Fimage007.png
- 图中平面DEFG为正垂面/sqp/img?f=0c1cca171831f76bf2102f2267474046.files%2Fimage009.png
- 现有两个振动,其振动方程如下: 若以上两振动的相位差满足时,则以下说法正确的是:/sqp/img?f=2c6cc223aa679137b25332cbbf7af925.files%2Fimage007.png/sqp/img?f=2c6cc223aa679137b25332cbbf7af925.files%2Fimage008.jpg