二极管的电流方程是
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举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 下列方程中是一阶微分方程的是[input=type:blank,size:4][/input]. 未知类型：{'options': ['[tex=8.0x1.571]SnLzj4UlSfnGqNtEzxfZSuZwslGsWxsvP2Y+yf7H578Vefe1Ol/nJT135DjkdnSNNikL3arAj80BjvPHaHCDiA==[/tex]', '[tex=10.571x1.571]JR4yrHJRIZfJXwhFSObwrfajFnWUvXzM/YiA3M6aDKuVBZ8I+7v5iXTXdA3E6Rm4vOE2BCfPwFP2rmRygXKEUDk1qLsNDCJ2p8GEbfCSr2s=[/tex]', '[tex=5.643x1.357]m0sKckxx+jZ9iltApBtB23TBISIOx/g0judcsS+akNFZrUNCq3g+BIVQwGbQEh/C[/tex]', '$y^{(4)}+5 y^{\\prime}-\\cos x=0$'], 'type': 102}
- [tex=1.857x1.0]1FVfIOJf7ISeQGf+8HT7Iw==[/tex]尿素的合成需消耗[tex=2.214x1.286]iLZ8dFzDhyDszs4Q6Iairw==[/tex]摩尔数是 未知类型：{'options': ['2', '3', '4', '5', '6'], 'type': 102}