• 2022-05-30
    设[tex=5.643x1.286]BgK3sG4MLAO2YnRnInPOXxLuiACNfbR2JMaJ22ckFBA=[/tex]是共线的五点,且两两不同,证明[tex=5.357x1.286]A5IYnKwlmfeGyycQuXAVFh4rVuNQcIbLGRGYA1S3/aQ=[/tex][tex=12.714x1.286]JZEo6tX1YSqEA8iSuq6wLsZpQYAsaHuYHMykuhybUezFWm2fVVAyR+U6dLWuuJAy[/tex] . 
  • 举一反三