• 2021-04-14
    以下代码的运行结果为
    def calculate(number):
    result = 0
    i = 1
    while i <= number:
    result = result + i
    i += 1
    return result
    result = calculate(100)
    print('1~100的累积和为:', result)
  • 5050

    内容

    • 0

      下面的方法,当输入为2的时候返回值是多少?( ) public static int getValue(int i) { int result = 0; switch (i) { case 1: result = result + i; case 2: result = result + i * 2; case 3: result = result + i * 3; } return result; }

    • 1

      以下代码执行的结果是:( )int i=2;int result = 0;switch (i) {case 1:result = result + i;case 2:result = result + i * 2;case 3:result = result + i * 3;}System.out.println(result); A: 0 B: 2 C: 4 D: 10

    • 2

      以下代码运行后,result的值为() var result = 0; for (var i = 2; i <=10; i+=2) { result *= i*i }

    • 3

      以下程序的运行结果为( ) #include&#91;stdio.h&#93; int main() { int answer,result; answer=100; result=answer-10; printf("The result is %i\n",result+5); return 0; }

    • 4

      esult = 0 for i in range(5): result += i print(result) 输出结果为( )