以下代码的运行结果为
def calculate(number):
result = 0
i = 1
while i <= number:
result = result + i
i += 1
return result
result = calculate(100)
print('1~100的累积和为:', result)
def calculate(number):
result = 0
i = 1
while i <= number:
result = result + i
i += 1
return result
result = calculate(100)
print('1~100的累积和为:', result)
5050
举一反三
- 以下代码中calculate()函数属于哪个分类 def calculate(number): result = 0 i = 1 while i
- 中国大学MOOC: 以下代码运行后,result的值为( )var result = 0;for (var i = 1; i <= 10; i++) {result = result * i}
- 下列程序的输出结果是:sum = 0 def sum(i1, i2): result = 0 for i in range(i1, i2 + 1): result += i return result print sum(1, 10)
- 下列语句的执行结果是: result = 0 i = 1 while result <; 10: result += i i += 1 if i >; 2: break print(result) A: 3 B: 5 C: 7 D: 10
- 以下代码运行后,result的值为( )var result = 0; for (var i = 1; i <;= 10;i++) { result = result * i } A: 0 B: 1 C: 9的阶乘 D: 10的阶乘
内容
- 0
下面的方法,当输入为2的时候返回值是多少?( ) public static int getValue(int i) { int result = 0; switch (i) { case 1: result = result + i; case 2: result = result + i * 2; case 3: result = result + i * 3; } return result; }
- 1
以下代码执行的结果是:( )int i=2;int result = 0;switch (i) {case 1:result = result + i;case 2:result = result + i * 2;case 3:result = result + i * 3;}System.out.println(result); A: 0 B: 2 C: 4 D: 10
- 2
以下代码运行后,result的值为() var result = 0; for (var i = 2; i <=10; i+=2) { result *= i*i }
- 3
以下程序的运行结果为( ) #include[stdio.h] int main() { int answer,result; answer=100; result=answer-10; printf("The result is %i\n",result+5); return 0; }
- 4
esult = 0 for i in range(5): result += i print(result) 输出结果为( )