举一反三
- 下面的代码段执行之后count的值是什么( ) int count = 1; for (int i = 1; i <= 5; i++) { count += i; } System.out.println(count);
- 下面的代码段执行之后count的值是什么( ) int count = 1; for(int i = 1; i <= 5; i++) { count+= i; } System.out.println(count); int count = 1; for(int i = 1; i <= 5; i++) { count+= i; } System.out.println(count);
- 下面的代码段执行之后count的值是什么？ int count = 0; for....out.println(count);
- 如果希望实现从1到10的累加,并得出结果;int count=0;_______{count +=i;}应该在空白处添加下面哪段代码?( ) A: for (int i=0; i<;10;i++) B: for (int i=0; i<;=9;i++) C: for (int i=1; i<;=10;i++) D: for (int i=1; i<;10;i++)
- 现有如下程序段: #include"stdio.h" main() {int k[30]={12,324,45,6,768,98,21,34,453,456}; int count=0,i=0; while(k[i]) {if(k[i]%2==0||k[i]%5==0)count++; i++;} printf("%d,%d\n",count,i);} 则程序段的输出结果为.
内容
- 0
写出下列程序的输出结果 public class Test { public static void main(String[] args) { Count myCount = new Count(); int times = 0; for(int i=0;i<100;i++) increment(myCount , times); System.out.println(“count is” + myCount.count); System.out.println(“time is”+ times); } public static void increment(Count c , int times) { c.count++; times++; } } class Count { public int count; Count(int c) { count =c; } Count() { count =1; } }
- 1
48. 以下Java代码片段编译运行的结果是。 int [] a = {1,2,3,4,5}; for (int count = 0 ; count<5; count ++) System.out.print(a[count++]) int [] a = {1,2,3,4,5}; for (int count = 0 ; count<5; count ++) System.out.print(a[count++])
- 2
代码中myCount.count的值为（A）?public class Test { public static void main(String[] args) { Count myCount = new Count(); int times = 0; for (int i=0; i<100; i++) increment(myCount, times); System.out.println("myCount.count = " + myCount.count); } public static void increment(Count c, int times) { c.count++; times++; }} class Count { int count; Count(int c) { count = c; } Count() { count = 1; }} A: 101 B: 100 C: 99 D: 98
- 3
下列程序的运行结果是（）。 public class Test public static void main ( String [ ] args ) int count = 0 for( int i = 1 i < 5 i = 2) for( int j = 1 j< = 10 j = 3) count System .out .print (count ) _
- 4
println 语句执行了多少次？ for (int i = 0; i < 10;i++) for (int j = 0;j < i；j++) System .out.println(i * j)