• 2022-05-25
    试求题图所示三角波信号的频谱函数[tex=2.357x1.357]Eq+9ymfvXVW2edo/3dIBzlAKNJML/Mf6RRWIUu7Z2n8=[/tex]。[img=209x163]17d958199fda8fb.png[/img]
  • 直接利用Fourier变换公式得[tex=26.714x6.071]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[/tex]

    内容

    • 0

      int x,y,z; x=7; y=8; z=9; if(x>y) x=y; y=z; z=x; printf(“x=%d y=%d z=%d\n”,x,y,z);以上程序段的输出结果是:() A: x=7 y=8 z=9 B: x=7 y=9 z=7 C: x=8 y=9 z=7 D: x=8 y=9 z=8

    • 1

      试求图 10-20 所示信号的频谱 [tex=2.643x1.357]BIC3RUBd9TcX9XqxJlxbpA==[/tex] 。[img=356x197]17d4cc481f90143.png[/img]

    • 2

      试求下图所示三角波信号的频谱函数。

    • 3

      设随机变量X的密度函数为[img=572x74]1791bc8f97085d2.jpg[/img]试求:(1)常数A;(2)[tex=6.714x1.357]AyFmD19eLybEpNdIrC346g==[/tex]

    • 4

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}