举一反三
- 设,在内,则在内（ ）/ananas/latex/p/243901/ananas/latex/p/22409/ananas/latex/p/243903/ananas/latex/p/2154/ananas/latex/p/22992
- 设Ω{1,2,…,10},{2,3,4},{3,4,5}，则/ananas/latex/p/1591/ananas/latex/p/37739/ananas/latex/p/37740/ananas/latex/p/502945
- 已知()=0.4，则()=( )/ananas/latex/p/152/ananas/latex/p/278/ananas/latex/p/847/ananas/latex/p/281/ananas/latex/p/152/ananas/latex/p/4781/ananas/latex/p/7419/ananas/latex/p/6547
- 设在上二阶可导，且,则在内是（ ）/ananas/latex/p/2154/ananas/latex/p/13269/ananas/latex/p/243898/ananas/latex/p/243899/ananas/latex/p/95388
- 设可微，且，则/ananas/latex/p/2154/ananas/latex/p/902448/ananas/latex/p/54324
内容
- 0
设,在D上可积，，则 , , .https://mooc1-1.chaoxing.com/ananas/latex/p/27236https://mooc1-1.chaoxing.com/ananas/latex/p/356004https://mooc1-1.chaoxing.com/ananas/latex/p/1153863https://mooc1-1.chaoxing.com/ananas/latex/p/1153883https://mooc1-1.chaoxing.com/ananas/latex/p/1153941https://mooc1-1.chaoxing.com/ananas/latex/p/1153969https://mooc1-1.chaoxing.com/ananas/latex/p/1153978
- 1
设 是正整数集合，，，则 f 。/ananas/latex/p/63479/ananas/latex/p/2116060/ananas/latex/p/2116061
- 2
设函数，则当时，是无穷大/ananas/latex/p/267831/ananas/latex/p/19796/ananas/latex/p/2154
- 3
设方程确定了函数，具有连续偏导数，且，则/ananas/latex/p/527160/ananas/latex/p/34531/ananas/latex/p/250503/ananas/latex/p/1069243/ananas/latex/p/653189
- 4
判断下列积分值的大小： , , , 其中由 围成，则之间的大小顺序为/ananas/latex/p/2133704/ananas/latex/p/2133724/ananas/latex/p/2133733/ananas/latex/p/279/ananas/latex/p/206314/ananas/latex/p/575706/ananas/latex/p/920218/ananas/latex/p/149974/ananas/latex/p/16447