• 2021-04-14
    输入正整数n,计算s = 1/1! + 1/2! + 1/3! + ……+ 1/n!的值。
    #include
    int main
    {
    int j, k, n;
    double f, s;
    scanf("%d", &n);

    s= (1) ;
    for (k=1; k<=n; k++)
    {
    f= (2) ;
    for(j=1; (3) ; j++)
    f= (4) ;
    s=s+1/f;
    }
    printf("sum=%f
    ", s);
    return 0;
    }