设有如下程序publicclasstest{publicstaticvoidmain(Stringargs[]){IntegerintObj=Integer.valueOf(args[args.length-1]);inti=intObj.intValue();if(args.length>1) System.out.println(i);if(args.length>0) System.out.println(i-1);elseSystem.out.println(i-2);}}运行程序,输入如下命令
举一反三
- 下列程序编译并运行的结果为()publicclassTest{publicstaticvoidmain(String[]args){try{inti=1;System.out.println(i++);}finally{System.out.println(++i);}}}
- 请阅读下面的程序，sum的值为（）publicclassTest{publicstaticvoidmain(String[]args){intsum=0;for(inti=1;i=100;i++){if(i%2==1){continue;}sum+=i;}System.out.println(sum=+sum);}}
- 中国大学MOOC: 下列代码中构造方法的返回类型是（）public class Village { Village () { System .out .println(“hiding in Village”) ; } public static void main( String args [ ]) { Village c =new Village ( ) ;}class Village { public static void main( String args [ ]) { Village c =new Village ( ) ; } Village () { System .out .println(“hiding in Village”) ; } }
- 下列程序的运行结果是（）。 public class Test public static void main ( String [ ] args ) int count = 0 for( int i = 1 i < 5 i = 2) for( int j = 1 j< = 10 j = 3) count System .out .print (count ) _
- 请看下面的程序代码,当 n 为( )值时,程序段将输出字符串 second。 [br][/br] switch(n) { [br][/br] case 0: System .out .println(“first”); [br][/br] case 1: [br][/br] case 2: System .out .println(“second”); break; [br][/br] default: System .out .println(“end”); [br][/br] }(2.0) A: 0 B: 1 C: 2 D: 以上都可以