一力F作用在平面OABC上(如图所示),于是力F对OX、OY、OZ三轴之矩应为()。
A: mx(F)=0,my(F)=0,mz(F)=0
B: mx(F)=0,my(F)=0,mz(F)≠0
C: mx(F)≠0,my(F)≠0,mz(F)=0
D: mx(F)≠0,my(F)≠0,mz(F)≠0
A: mx(F)=0,my(F)=0,mz(F)=0
B: mx(F)=0,my(F)=0,mz(F)≠0
C: mx(F)≠0,my(F)≠0,mz(F)=0
D: mx(F)≠0,my(F)≠0,mz(F)≠0
举一反三
- 图示力F的作用线在OABC平面内,此力对各坐标轴之矩为()。[img=566x480]17e0ba674f72d05.png[/img] A: Mx(F)≠0,My(F)≠0,Mz(F)≠0 B: Mx(F)≠0,My(F)≠0,Mz(F)=0 C: Mx(F)≠0,My(F)=0,Mz(F)=0 D: Mx(F)=0,My(F)=0,Mz(F)=0
- 若一个空间力与x轴相交,但不与y轴、z轴平行和相交,则它对三个坐标轴之矩应是()。 A: Mx(F)≠0、My(F)≠0、Mz(F)≠0 B: Mx(F)=0、My(F)≠0、Mz(F)≠0 C: Mx(F)=0、My(F)=0、Mz(F)≠0 D: Mx(F)=0、My(F)≠0、Mz(F)=0
- 力F作用在OABC平面内,x轴与OABC平面成q角(q=60°),如图,则力F对三轴之矩为()。 A: Mx=0,My=0,Mz≠0 B: Mx=0,My≠0,Mz=0 C: Mx≠0,My=0,Mz=0 D: Mx≠0,My=0,Mz≠0
- 力F作用在OABC平面内,x轴与OABC平面成q 角(q = 90°),如图,则力F对三轴之矩为( )。[img=169x144]17e0ae97851da76.jpg[/img] A: Mx = 0,My = 0,Mz≠0; B: Mx = 0,My≠0,Mz = 0; C: Mx≠0,My = 0,Mz = 0; D: Mx≠0,My = 0,Mz≠0。
- 若已知力F对直角坐标系原点O的力矩矢的大小∣MO(F)∣,方向沿Oy向,则此力对此坐标系中各轴的矩为()。 A: Mx(F)=0, My(F)=0,Mz(F)=0 B: Mx(F)=0,M y(F)= ∣MO(F)∣,Mz(F) =∣MO (F)∣ C: Mx(F)=0,My(F)= ∣MO(F)∣,MZ(F)=0 D: Mx(F)=0,My(F)=0, Mz(F)= ∣MO(F)∣