若用力矩分配法计算图示刚架,则结点A的不平衡力矩为：[img=260x227]18035f0a0066787.jpg[/img]
A: [img=80x48]18035f0a0cca7fd.jpg[/img]
B: [img=49x45]18035f0a17397a2.jpg[/img]
C: [img=92x44]18035f0a22a9a8a.jpg[/img]
D: [img=43x43]18035f0a2e08358.jpg[/img]
A: [img=80x48]18035f0a0cca7fd.jpg[/img]
B: [img=49x45]18035f0a17397a2.jpg[/img]
C: [img=92x44]18035f0a22a9a8a.jpg[/img]
D: [img=43x43]18035f0a2e08358.jpg[/img]
举一反三
- 若f(x)+f(-x)=0, 则[img=95x39]17da608af452d96.jpg[/img]. 若f(x)=f(-x), 则 [img=170x38]17da60541207426.jpg[/img]
- 在下列命题中:如果f(x)=[img=28x44]17e0bf9914bb2f1.png[/img],那么[img=27x29]17e0bf97582597b.png[/img]f(x)=0;如果f(x)=[img=28x44]17e0bf992111a1c.png[/img],那么[img=27x29]17e0bf97582597b.png[/img]f(x)=0;如果f(x)=[img=55x44]17e0bf992d8de0a.png[/img],那么[img=29x29]17e0bf9939482bb.png[/img]f(x)不存在;如果f(x)=[img=87x53]17e0bf99450fa82.png[/img],那么[img=27x29]17e0bf97582597b.png[/img]f(x)=0。其中错误命题的个数是( A: 0 B: 1 C: 2 D: 3
- 若用力矩分配法计算图示刚架,则结点A的不平衡力矩为：[img=260x227]1803761d253e3fe.jpg[/img] A: [img=80x48]1803761d2fb9a6c.jpg[/img] B: [img=49x45]1803761d3afc7d3.jpg[/img] C: [img=92x44]1803761d45fd1c6.jpg[/img] D: [img=43x43]1803761d51617c6.jpg[/img]
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- 若用力矩分配法计算图示刚架,则结点A的不平衡力矩为：[img=260x227]18038cc45e719e7.jpg[/img] A: [img=80x48]18038cc46869ef5.jpg[/img] B: [img=49x45]18038cc473626f6.jpg[/img] C: [img=92x44]18038cc47eda22b.jpg[/img] D: [img=43x43]18038cc48adb740.jpg[/img]