It is assumed that, in a concrete pavement normal vectors of the neutral surface are always perpendicular to the neutral surface, and therefore no （） strain in horizontal directions
A: normal
B: shear
C: elastic
D: plastic
A: normal
B: shear
C: elastic
D: plastic
举一反三
- Due to the pure bending deformation, the longitudinal ( ) strain varies ( ) from ( ) at the neutral axis to a maximum at the outer fibers of the beam. A: normal; linearly; zero B: shear; nonlinearly; zero C: shear; nonlinearly; zero D: shear; nonlinearly; zero
- The flexure formula is based on the requirement that the ( ) on the cross section is equal to the ( ) produced by the ( ) distribution about the neutral axis.? resultant moment; moment; linear normal stress|resultant moment; moment; nonlinear normal stress|resultant moment; moment; nonlinear shear stress|resultant normal force; force; linear normal stress
- Normal strain cause a change in of the rectangular element, whereas the shear strain cause a change in its .
- The cross section of a straight beam remains plane when the beam deforms due to bending. This causes ( ) on one side of the beam and ( ) on the other side. The neutral axis is subjected to ( ) .? normal stress; shear stress; zero stress|tensile stress; compressive stress; zero stress|compressive stress; tensile stress; maximum normal stress|shear stress; normal stress; zero stress
- On the surface of a perfect conductor, the normal component of the electric displacement vector is A: continuous with the normal component of the electric displacement vector inside the conductor B: uncertain C: equal to the surface density of free charge on the conductor surface. D: equal to zero