如①所示，填充以下空白。[tex=13.0x1.5]fTh60CRnhLWobDH0vvVn5LZTYGXLt906L4njqAKzJRv6n6wReg834JNhYtAFx45i6taOAuw3WWdlBltALTQTagpG0SPhG1YhA2fZD88qGyE/wD0zQJzMNxanQIh+rGpsdxz0+wPAlUILoy8TaYDxbifygiWgEqYXT5dgARobuUCd+iVmvzO4Qp+oxqxQfjM+[/tex]② [tex=15.571x1.571]UpgbneWnRVFeVe2DQdP9TWUAoTz10l26P8XKEIsAly0tzPsPrc0aXSvxC0PFwragSMzNmboGB+tSVU6cZM3R5Dcp5L1F5owTELpHbk7LIYY=[/tex]
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 下面是图的拓扑排序的是？(多选)[img=340x240]1802faef6ebcc2a.png[/img] A: 2 8 0 7 1 3 5 6 4 9 10 11 12 B: 2 8 7 0 6 9 11 12 10 1 3 5 4 C: 8 2 7 3 0 6 1 5 4 9 10 11 12 D: 8 2 7 0 6 9 10 11 12 1 3 5 4
- 以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9
- list(range(-1,10,2)) A: [0, 2, 4, 6, 8, 10] B: [-1, 1, 3, 5, 7, 9] C: [0, 2, 4, 6, 8]
- for (int i = 1; i <= 10; i++){ if (i % 5 != 0) continue; Console.WriteLine("{0}", i); }该段程序执行后输出_____。 A: 5 10 B: 1 2 3 4 6 7 8 9 C: 5 D: 1 2 3 4 5 6 7 8 9 10