A: cAMP-CAP is bound to the promoter;
B: cAMP-CAP is not bound to the promoter;
C: The repressor is not bound to the operator;
D: The lac operon is turn on
举一反三
- Operator is bound by A: activator B: repressor C: promoter D: enhancer E: silencer
- In prokaryotic cells, the DNA sequence which can be recognized and bound with RNA polymerase is called ( ) A: enhancer B: promoter C: silencer D: operator E: attenuator
- cAMP在乳糖操纵子中的作用是:() A: 转变为 CAP, 发挥作用 B: 于 CAP 结合, 形成 cAMP-CAP 复合物发挥作用 C: 使阻遏蛋白变构 D: 作为第二信使发挥作用
- cAMP在乳糖操纵子中的作用是() A: 转变为CAP,发挥作用 B: 于CAP结合,形成cAMP-CAP复合物发挥作用 C: 使阻遏蛋白变构 D: 作为第二信使发挥作用
- Operon do not include( ): A: promoter B: regulatory sequence C: operator D: structural gene E: trans-acting factor
内容
- 0
The operator is A: Another name for the terminator of a gene B: A DNA site bound by repressor proteins C: A protein that coordinates gene expression D: A part in the leader region of mRNA
- 1
Operator: ( ) A: An operator is a DNA region that is working with promoter for genes to express. B: An operator is a DNA region at 5’ of a gene for a repressor to bind to prevent gene expression. C: An operator is a repressor protein to help genes to express. D: An operator is a repressor protein to inhibit genes to express.
- 2
能与阻遏蛋白相结合的调控序列,叫做 A: RBS B: operon C: promoter D: operator E: SD序列
- 3
以下关于cAMP对原核基因转录的调控作用的叙述错误的是() A: cAMP可与分解代谢基因活化蛋白(CAP)结合成复合物 B: cAMP-CAP复合物结合在启动子前方 C: 葡萄糖充足时,cAMP水平不高 D: 葡萄糖和乳糖并存时,细菌优先利用乳糖 E: cAMP-CAP对乳糖操纵子的调节属于正性调节
- 4
以下关于cAMP对原核基因转录的调控作用的叙述不正确的是()。 A: 葡萄糖和乳糖并存时,细菌优先利用乳糖 B: cAMP可与分解代谢基因活化蛋白(CAP)结合成复合物 C: 葡萄糖充足时,cAMP水平不高 D: cAMP-CAP复合物结合在启动子前方 E: cAMP-CAP对乳糖操纵子的调节属于正性调节