已知:H2(g)+Br2(g)→2HBr(g),DrHmy(1);H2(g)+Br2(l)→2HBr(g),DrHmy(2);则DrHmy(1)与DrHmy(2)的关系是( )
A: DrHmy(1)DrHmy(2)
B: DrHmy(1)=-DrHmy(2)
C: DrHmy(1)=DrHmy(2)
D: DrHmy(1)DrHmy(2)
A: DrHmy(1)DrHmy(2)
B: DrHmy(1)=-DrHmy(2)
C: DrHmy(1)=DrHmy(2)
D: DrHmy(1)DrHmy(2)
举一反三
- 已知H2O (l) = H2 (g) +1/2 O2 (g) DrHmy = 285.8 kJ·mol–1 则反应2 H2 (g) + O2 (g) = 2H2O (l) 的 DrHmy 为 ( ) A: 285.8 kJ·mol–1 B: - 285.8 kJ·mol–1 C: 571.6 kJ·mol–1 D: - 571.6 kJ·mol–1
- 11.某温度时H2(g)+ Br2(g)⇌2HBr(g)的Kp=4×10-2,则反应HBr(g)⇌1/2H2(g)+1/2 Br2(g)的Kp是( B)。 A: 1/4×10-2 B: 1/[(4×10-2)1/2] C: (4×10-2)1/2 D: 2×10-1
- 某温度时,反应H 2 (g) + Br 2 (g) == 2HBr(g)的Kc=4×10 -2 ,则反应 HBr(g) —— 1/2H 2 (g) + 1/2Br 2 (g) 的Kc为 ( )
- 下列过程的DrHmy在数值上等于晶格能的是( ) A: NaBr(s)→Na+(s)+1/2Br2(l) B: NaBr(s)→Na(g)+Br(g) C: NaBr(s)→Na+(g)+Br-(g) D: NaBr(s)→Na(g)+1/2Br2(g)
- 已知DfHmy(CH3OH,l,298K)= -239 kJ·mol-1,DfHmy(CO,g,298K)= -111 kJ·mol-1,则反应CO(g)+2H2(g)=CH3OH(l)的DrHmy( 298K)等于: