查询性别为男的信息，条件怎么写
A: where sex !=’男'
B: where sex not in 男
C: where sex ='男'
D: where sex between 男
A: where sex !=’男'
B: where sex not in 男
C: where sex ='男'
D: where sex between 男
举一反三
- 下面 语句和”select * from student where sex=’男’ && age=20;”语句查询出的结果是一样的。（ ） A: select * from student where sex=’男’ or age=20; B: select * from student where sex=’男’ || age=20; C: select * from student where sex=’男’ and age=20; D: select * from student where sex,age in(’男’,20);
- 数据库中有一张表名称为Student，有列Name，Age，IDCard，Sex。要求查询所有男同学信息，下列哪个SQL语句是正确的 A: Select * From Student Where Sex '男' B: Select * From Student Where Sex ='女' C: Select * From Student Where Sex In '男' D: Select * From Student Where Sex ='男'
- 数据库中有一张表名称为Student，有列Number，Name，Age，IDCard，Sex。主键为Number。要求查询所有男同学信息，下列哪个SQL语句是正确的？（） A: ASelect* From Student Where Sex=’男’ B: BSelect* From Student Where Number NotIn（Select Number From Student Where Sex<>=’男’） C: CSelect* From Student Where NumberIn（Select Numbe rFrom Student Where Sex=’男’） D: DSelect* From Student Where Sex<>’男’
- 统计各系男生人数,最准确的SQL语句是(<br/>)。 A: SELECT<br/>COUNT(*) FROM stduents GROUP BY d_no WHERE sex='男' B: SELECT<br/>COUNT(*) FROM students WHERE sex='男'<br/>GROUP BY d_no C: SELECT<br/>COUNT(*) FROM students WHERE sex='男'<br/>ORDER BY d_no D: SELECT<br/>COUNT(*) FROM students HAVING sex='男'<br/>GROUP BY d_no
- 显示所有男生的信息，不正确的命令是？ A: db.students.find({"sex":"男"}) B: db.students.find("this.sex=='男' ") C: db.students.find({"this.sex='男' "}) D: db.students.find({$where:"this.sex=='男' "})