在通过next[j]计算next[j+1]的递推过程中next[j+1] == next[j] + 1当且仅当：
A: j = 0
B: P[j] = P[next[j] - 1]
C: T[j] = P[j]
D: P[j] = P[next[j]]
A: j = 0
B: P[j] = P[next[j] - 1]
C: T[j] = P[j]
D: P[j] = P[next[j]]
举一反三
- 令 A = {t | P[0, t) = P[j - t, j)} ，即A是所有使得P[0,j)的前缀与后缀相等的长度t，如何计算next[j]？ A: next[j] = min A B: next[j] = max A C: next[j] = |A| (A中的元素个数) D: next[j] = max A - |A|
- 下面____程序段不能正确显示1!、2!、3!、4!的值。 A: For I=1 To 4 n=1 For j=1 to I n=n*j Next j Print n Next I B: For I=1 To 4 For j=1 to I n=1 n=n*j Next j Print n Next I C: n=1 For j=1 to 4 n=n*j Print n Next j D: n=1:j=1 Do While j<=4 n=n*j Print n j=j+1Loop
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- 下列程序段不能正确显示1！、2！、3！、4！的结果的是 。 A: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox( n)Next i B: Dim i%, j%, n%For i = 1 To 4 n = 1 For j = 1 To i n = n * j Next j MsgBox( n)Next i C: Dim j%, n%n = 1For j = 1 To 4 n = n * j MsgBox( n)Next j D: Dim j%, n%n = 1j = 1Do While j<=4 n=n*j MsgBox(n) j=j+1Loop E: Dim j%, n%n = 1j = 1Do n=n*j MsgBox(n) j=j+1Loop While j<=4
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