A（n） ___ term can be either positive or negative.
A: A = assuring term
B: G = guarding term
C: D = discounting term
D: E = evaluative term
A: A = assuring term
B: G = guarding term
C: D = discounting term
D: E = evaluative term
举一反三
- 下面程序流程图的功能是利用下面的公式计算e的近似值,直到最后一项的绝对值小于时为止,则下图中空白的矩形框内应该填写的是()。 A: term=term*n B: term=term/n C: term=1/term D: term=1/term*n
- 以下求1*2*3......*20的程序正确的是: A: main(){inti,term;i=1;term=0;do{term=term*i;i++;}while(i<=20)<p="">printf("t=%d",term);} B: main(){inti,term;i=1;term=1;do{term=term*i;i++;}while(i<=20)<p="">printf("t=%d",term);} C: main(){inti,term;term=1;for(i=1,i<=20,i++)<p="">{term=term*i;i++;}printf("t=%d",term);} D: main(){inti,term;term=1;for(i=1;i<=20;i++)<p="">{term=term*i;i++;}printf("t=%d",term);}
- The term of <br/>”Description of Goods” is the contract’s( ) A: Quality term B: Quantity term C: Name of the<br/>commodity term D: Description term
- 下面程序流程图的功能是利用下面的公式计算e的近似值，直到最后一项的绝对值小于[img=56x36]18031e653a8d847.jpg[/img]时为止， [img=154x39]18031e6546bdef9.jpg[/img]则下图中空白的矩形框内应该填写的是（ ）。[img=116x216]18031e655136ee4.jpg[/img] A: term = term / n B: term= 1 / term*n C: term= 1 / term D: term = term * n
- 下面程序流程图的功能是利用下面的公式计算e的近似值，直到最后一项的绝对值小于[img=56x36]1802d1bdc7edea3.jpg[/img]时为止， [img=154x39]1802d1bdd373c89.jpg[/img]则下图中空白的矩形框内应该填写的是（ ）。[img=116x216]1802d1bdde8a647.jpg[/img] A: term = term / n B: term= 1 / term*n C: term= 1 / term D: term = term * n