求方程Dy/Dx=y(y-1),y(0)=1的解
举一反三
- 求已知函数y=f(x)由方程y^2-2xy+9=0确定,求dy/dx
- 函数\(z = {x^y}\)的全微分为 A: \(dz = y{x^{y - 1}}dy + {x^y}\ln xdx\) B: \(dz = y{x^{y - 1}}dx + {x^y}dy\) C: \(dz = y{x^{y - 1}}dx + {x^y}\ln xdy\) D: \(dz = y{x^{y - 1}}dy + {x^y}dx\)
- 方程x(y2-1)dx+y(x2-1)dy=0的所有常数解是 A: y=±1,x=±1 B: y=±1 C: x=±1 D: y=1,x=1
- 设方程siny+ex(x次方)-xy2(平方)=0确定隐函数y=y(x),求dy/dx
- 求导数,y=1+xe^y,求dy/dx