17d625100987f5a.png图示开环[img=264x163]17d6251014f7dd2.png[/img]Nyquist曲线的穿越次数为( )
A: N+ =1,N-= 0
B: N+ =1,N-= 1
C: N+ =0,N-= 0
D: N+ =0,N-= 1
A: N+ =1,N-= 0
B: N+ =1,N-= 1
C: N+ =0,N-= 0
D: N+ =0,N-= 1
举一反三
- 17d6251071655b0.png图示开环传递函数[img=800x181]17d625107d5530b.png[/img],对应Nyquist曲线的穿越次数为( ) A: N+ =1,N-= 0 B: N+ =0,N-= 1 C: N+ =1,N-= 1 D: N+ =0,N-= 0
- 17d6250f7313c59.png开环[img=584x164]17d6250f808af75.png[/img]Nyquist曲线绘制如图所示,其穿越次数为( ) A: N+ =1/2,N-= 1/2 B: N+ =0,N-= 1/2 C: N+ =1/2,N-= 0 D: N+ =0,N-= 0
- 17d6251022f7288.png已知开环[img=632x180]17d625102f775e7.png[/img]Nyquist曲线图,可以分析出其穿越次数为( ) A: N+ =1,N-= 1 B: N+ =0,N-= 0 C: N+ =0,N-= 1 D: N+ =1,N-= 0
- 17d62511f163f35.png对该图所示开环[img=468x180]17d62511fe7fe57.png[/img],仔细分析,可以发现其Nyquist曲线的穿越次数为( ) A: N+ =0,N-= 1 B: N+ =0,N-= 0 C: N+ =1,N-= 0 D: N+ =1,N-= 1
- 17da713c5da10b6.png结合开环[img=448x176]17da713c717a4b4.png[/img]Nyquist曲线图,利用频域稳定性判据中关于穿越的定义,可以得出其穿越次数为( ) A: N+ =0,N-= 1 B: N+ =0,N-= 0 C: N+ =1,N-= 0 D: N+ =1,N-= 1