• 2022-06-15
    Oneday,young,HowardKellywhowassellinggoodsfromdoortodoortopayhiswaythroughschool,foundhehadonlyonethincoinleft,andhewashungry.Hedecidedhewouldaskforamealatthenexthouse.However,helosthiscouragewhenalovelyyoungwoman,openedthedoor.Insteadofamealheaskedfor;somewater.Shethoughthe,lookedhungrysoshebroughthimalargeglassofmilk.Hedrankitslowly,andthenasked,“Howmuchdo,Ioweyou?”“Youdon’t,owemeanything,”shereplied.“Motherhastaughtusnevertoacceptpayforakindness.”Hesaid,“ThenIthankyoufrommyheart.”AsHowardKellyleftthathouse,henotonlyfeltstrongerphysically,buthisfaithinpeoplewasstrengthenedalso.Hehadbeenreadytogiveupandleave.Yearslater,thatwomanbecameseriouslyill.Thelocaldoctorsweregreatlypuzzled.Theyfinallysenthertothebigcity,wheretheycalledinexpertstostudyherraredisease.Dr.HowardKellywascalledinfortheconsultation.Whenheheardthenaiveofthetownshecamefrom,thelightofrecognitionfilledhiseyes.Immediately,heroseandwentdownthehallofthehospitaltoherroom.Dressedinhisdoctor’sclotheshewentintoseeher.Herecognizedheratonce.Hewentbacktotheconsultationroomevenmoredeterminedtodohisbesttosaveherlife.Fromthatdayonhegavespecialattentiontoherdisease.Afteralongstruggle,thebattlewaswon.Dr.Kellyrequestedthebusinessofficetopassthefinalbilltohimforapproval.Helookedatit,andthenwrotesomethingontheedge,andthebillwassenttoherroom.Shefearedtoopenit,forshewassureitwouldtaketherestofherlifetopayforitall.Finallyshelooked,andsomethingcaughtherattentiononthesideofthebill.Shereadthesewords:“Paidinfullwithoneglassofmilk.”(Signed)Dr.HowardKelly.Tearsofjoyfloodedhereyesasherhappyheartprayed:ThankyouGod.Yourlovehasspreadthroughhumanheartsandhands.
  • BCADB答案解析:

    内容

    • 0

      一个能接受LRD指令的机器人程序,以下能让机器人回到原点的程序是: A: DL DR DL DR D B: DDR DR DR DDL DL D C: DDDR DR DDR DDL D D: DR DL DDR DDL DDDR DDDL

    • 1

      关于OSPF中DR的说法不正确的是( ) A: 通过hello报文选举DR B: 如果某路由器优先级比DR优先级高,但启动晚,它会抢占原来的DR自己成为DR C: 一个广播类型网络中只能有一个DR D: 一旦DR失效,BDR接替DR的工作,并重新选举一个BDR

    • 2

      质点作曲线运动,在时刻t 质点的位矢为r,速度为v ,速率为v,t 至(t +Δt)时间内的位移为Δr, 路程为Δs, 位矢大小的变化量为Δr ( 或称Δ|r|).根据上述情况,则必有(  ) A: |Δr|= Δs = Δr B: |Δr|≠ Δs ≠ Δr,当Δt→0 时有|dr|= ds ≠ dr C: |Δr|≠ Δr ≠ Δs,当Δt→0 时有|dr|= dr ≠ ds D: |Δr|≠ Δs ≠ Δr,当Δt→0 时有|dr|= dr = ds

    • 3

      质点作曲线运动,在时刻t质点的位矢为r,速度为v,速率为v,t至t+Δt时间内的位移为Δr,路程为Δs,位矢大小的变化量为Δr。则下列选项正确的为( ) A: │Δr│=Δs=Δr B: │Δr│≠Δs≠Δr ,当Δt→0时有│dr│=ds ≠ dr C: │Δr│≠Δs≠Δr ,当Δt→0时有│dr│= dr ≠ ds D: │Δr│=Δs≠Δr ,当Δt→0时有│dr│= dr = ds

    • 4

      23() A: Dr Madison is absent from the conference. B: Dr Madison is an expert on economics. C: Dr Madison will present our view of global economy. D: Dr Madison will preside over the conference this afternoon.