• 2022-06-09
    求变上限函数[img=72x35]17da5f1066e9acf.png[/img]对变量x的导数,实验命令是().
    A: diff(int(sqrt(a+t),t,x,x^2))ans =2*x*(x^2 + a)^(1/2) - (a + x)^(1/2)
    B: syms a t; diff(int(sqrt(a+t),t,x,x^2))ans =2*x*(x^2 + a)^(1/2) - (a + x)^(1/2)
    C: diff('int(sqrt(a+t)','t',x,x^2))ans =2*x*(x^2 + a)^(1/2) - (a + x)^(1/2)
  • B

    内容

    • 0

      函数\(y = {\left( {\arcsin x} \right)^2}\)的导数为( ). A: \(2\arcsin x{1 \over {\sqrt {1 - {x^2}} }}\) B: \( - 2\arcsin x{1 \over {\sqrt {1 - {x^2}} }}\) C: \(2\arcsin x{1 \over {\sqrt {1 + {x^2}} }}\) D: \( - 2\arcsin x{1 \over {\sqrt {1 + {x^2}} }}\)

    • 1

      已知“syms t; x=cos(t); y=sin(t); z=t; xt=diff(x,'t'); yt=diff(y,'t'); zt=diff(z,'t'); f=z^2/(x^2+y^2); g=sqrt(xt^2+yt^2+zt^2); I=int(f*g,t,0,2*pi)”,则下列说法正确的是【】

    • 2

      将[img=83x51]17de8a0fc777b0b.png[/img]表示为程序所能接受的表达式,正确的为 A: sqrt(pow(x, 2) / (pow(x, 2) + 1)) B: sqrt(pow(2, x) / (pow(2, x) + 1)) C: pow(sqrt(2, x) / (sqrt(2, x) + 1)) D: pow(sqrt(x, 2) / (sqrt(x, 2) + 1))

    • 3

      求函数$y = \root 3 \of {x + \sqrt x } $的导数$y' = $( ) A: ${{1 + 2\sqrt x } \over {\root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ B: $ {{1 + 2\sqrt x } \over {6\root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ C: $ {{1 + 2\sqrt x } \over {6\sqrt x \cdot \root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$ D: $ {{1 + 2\sqrt x } \over {\sqrt x \cdot \root 3 \of {{{\left( {x + \sqrt x } \right)}^2}} }}$

    • 4

      函数\(y = \arcsin x\)的导数为( ). A: \( - {1 \over {\sqrt {1 + {x^2}} }}\) B: \({1 \over {\sqrt {1 + {x^2}} }}\) C: \({1 \over {\sqrt {1 - {x^2}} }}\) D: \( - {1 \over {\sqrt {1 - {x^2}} }}\)