求圆盘[tex=5.643x2.0]qgh6cWm2HfWz24TaQJF2nrM62Z6b1s/B5ou0vjQujR0=[/tex]绕[tex=0.5x1.0]iwXm0SwS+lfupyC0IyH8yQ==[/tex]轴旋转的旋转体的体积

2022-06-10

求圆盘[tex=5.643x2.0]qgh6cWm2HfWz24TaQJF2nrM62Z6b1s/B5ou0vjQujR0=[/tex]绕[tex=0.5x1.0]iwXm0SwS+lfupyC0IyH8yQ==[/tex]轴旋转的旋转体的体积

答案：

由[tex=5.643x2.0]iWfFVeEmDOBR+PqJRNWa0CMvFRmImSPocpy6K/drzCw=[/tex]得[tex=6.357x1.643]oM1wZAnMKsVVHG5GIMj18Wlczs+G7xjgqiLJwMRV8oA=[/tex]，如图所示，[img=192x162]1776ba86fc368dc.png[/img]故旋转体的体积为[tex=22.143x2.857]M8Nlu5zwoUG3iOx+P1kHv9WodRMP/MuIAkSp1OOGv4+WzRnwfpz+1Lr/XBLZsRqDnHx5w5VrDzdxIH3ncNUKjGjpGTS3AXd87Qx6dKSTogX+ts7B0VqT7bR1eEVyDRSvEPkaJdzGkcQe45tXKbcfQVR2NL4MP5lUCDXtiY8AsZjbwRZbVu+L6fJS9npnDn4M[/tex][tex=19.714x2.857]fflc2pdMattIJit/0oKe/dzUJf9HICtZOSWTzYC/JrSNdzaC5GXovkFQiNdVrIehSWIT7bIy4Plz820FE3N9sLMEUhtEWtqk5M06u/KBEfHbaJM5/hKjSF0P6yHVwSYym7wRapWIOQ4et5SG2n7kqLD+M9O/CObgKFudcDEzqF0=[/tex]

举一反三

内容

0
求曲线[tex=6.786x1.214]zCpxDt7leu+TU1gGqkkjg5LCO67ZNBAOQE3v+e3MpIs=[/tex]及2[tex=0.571x0.786]c5VsltFnl9nO0qB/vNKOWA==[/tex]轴所围成的平面图形绕[tex=0.5x1.0]iwXm0SwS+lfupyC0IyH8yQ==[/tex]轴旋转所成的立体的体积.
1
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