• 2022-06-14
    设分段函数[tex=9.286x3.357]w70lG1NUs5ZRhKHaXMaifahNYA2l55OVx/YI5vl5IU4Z64gRLKvhclOtJ9DnA6b4/YS4FyFCO3kr3jIMcLGPvSzXLe45CDGWyV6LoGPSy8NdJpbgM+MxElJ8lTaULxWl[/tex]求导数[tex=2.214x1.429]U93ae75fuTDIyESpUsh0ZsDgKDbdXIcbBWW+plOs3hY=[/tex].