图示电路中,已知:R1 = 50 W,R2 = R3 = 30 W,R4 = 60 W,US = 60 V,IS = 3 A。用 叠加原理求各未知支路电流分别是( )。[img=205x156]1803da58c715bf1.png[/img]
A: I1 =-2.1 A I2 =0.9 A I3 =0.6 A I4 =0.3 A
B: I1 = 2.1 A I2 =-0.9 A I3 =-0.6 A I4 =-0.3 A
C: I1 = 2.1 A I2 =0.9 A I3 =0.6 A I4 =-0.3 A
D: I1 = -2.1 A I2 =0.9 A I3 =0.6 A I4 =-0.3 A
E: I1 = 2.1 A I2 =0.9 A I3 =-0.6 A I4 =0.3 A
A: I1 =-2.1 A I2 =0.9 A I3 =0.6 A I4 =0.3 A
B: I1 = 2.1 A I2 =-0.9 A I3 =-0.6 A I4 =-0.3 A
C: I1 = 2.1 A I2 =0.9 A I3 =0.6 A I4 =-0.3 A
D: I1 = -2.1 A I2 =0.9 A I3 =0.6 A I4 =-0.3 A
E: I1 = 2.1 A I2 =0.9 A I3 =-0.6 A I4 =0.3 A
举一反三
- 图示电路中,已知:R1 = 50 W,R2 = R3 = 30 W,R4 = 60 W,US = 60 V,IS = 3 A。用 叠加原理求各未知支路电流分别是( )。[img=205x156]18030b91d98c0a8.png[/img] A: I1 =-2.1 A I2 =0.9 A I3 =0.6 A I4 =0.3 A B: I1 = 2.1 A I2 =-0.9 A I3 =-0.6 A I4 =-0.3 A C: I1 = 2.1 A I2 =0.9 A I3 =0.6 A I4 =-0.3 A D: I1 = -2.1 A I2 =0.9 A I3 =0.6 A I4 =-0.3 A E: I1 = 2.1 A I2 =0.9 A I3 =-0.6 A I4 =0.3 A
- 某多级减速器各级速比i1=2、i2=3、i3=4、i4=3,则总速比()。 A: i=i+i+i+i=12 B: i=i×i×i×i=72 C: i=3(i+i+i)=48 D: 不能求得
- I1=1,I2=-3,I3=4,I4=3,I5=?[img=428x301]17e0a8d664fb537.png[/img] A: 1 B: -1 C: 2 D: 0
- A.{{I1,I2,I3},{I1,I2,I4},{I1,I3,I4}}B.{{I1,I2,I3},{I1,I3,I4},{I2,I3,I4}}C.{{I1,I2,I3},{I1,I2,I4}}D.{{I1,I2,I3},{I1,I3,I4}}
- A.{{I1,I2,I3},{I1,I2,I4},{I1,I3,I4}}B.{{I1,I2,I3},{I1,I3,I4},{I2,I3,I4}}C.{{I1,I2,I3},{I1,I2,I4}}D.{{I1,I2,I3},{I1,I3,I4}}