解: 本例电路中包含两个无伴电流源支路(其中一个是受控电流源）,为使它们分别只属于某一个回路,可按图(b)所示选择基本回路(图中加甫的支路为相应的树支路),则回路 1 的电流[tex=2.214x1.214]N9NeDt6/601UAa1zW43/Eg==[/tex]回路2的电流[tex=2.929x1.214]mP60+lvBxistfFcUpB46pA==[/tex]对回路3[tex=20.214x1.357]SG8PbMDUCLTD7MssyxzkIPn9q8ntDWIHMOgO3Mr7iq5l6sfNNCHN+Il2M7CzPknvCaF18HdOwn4um94Ti9mG68LMfG9Yo0qF6qQ1KFpN38TK2vI2bbfzVz0JTij6K4TL[/tex]即[tex=19.214x1.357]/r4l+G/WcrI0Kbt7hhm+XDeVEmdeymDp0SSRShdColVSiQ2UnhXEJGPfrsbSNFYT5KjUmWy8bePrqyhKoPyT3PhcC90jHvluSKqDqjpWCAZCdIKvIPkiOOKwPz7KmAHo5eEFBctDU60orqd75ptOeQ==[/tex]对回路4[tex=22.5x2.786]jkbzK0rhPdgSKX6adier4fWKu727Vkyft6VW3qUsYeZZ4BBB/hCsagj0shU3V4FBL5NKgDno+fmwycVV/PsGvDGluVwr6qF+NYariot98x7JCDcsNDMnq09ok2RGcL5Krxon7X01d9xWQh2Jo5ZZs32sUvosc8gJmMFsBPupN9xDl7jy8fHSi2ig+tuS6w/0+DHzvbU8tu1S4M/aScKwSKhcVzuy+cSIFMtFQ3CMaTU=[/tex]将受控电源的控制盒用回路电流表示[tex=7.429x1.357]aY9RZ3etEeT/U8K3rsthVt42nLRI8OjjnnQhyDlu3ZJSPdjBSsMsXlp8Phjj03Sx[/tex]即[tex=8.143x4.071]xZhi2PnHFE0nJAXjFQiXj6OadP3l4xJk09MPPmcztksndgQjC6UKaHCjJI4FJab+gGx9p6iMbBwyDgVC2rMMFMzMO0i35SeLY2nhml04ezTpaehxMgRmJyi4ihbhZgyMe5FLkIiSl6tazw9VOgXluw==[/tex]代人回路 3 和 4 的方程并整理得[tex=20.643x9.643]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[/tex]