假设Smith的效用函数为[tex=6.143x1.357]AEgayOWT527Wjn5VPMrsNPz0y3OFaq2Hbd44oky4aUc=[/tex],收人为24，商品的价格分别为[tex=2.5x1.214]mqivdzfsW5sfuC+0azftYw==[/tex]和[tex=2.357x1.214]m4cDjKjQUNSPHrNbeX4psA==[/tex]，则Smith的最优消费组合为 。
未知类型：{'options': ['[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+arxaBDEswO8q8DbNbDgMQOI3O9rqGkzl7Ga+CPFfZV3WQ[/tex]', '[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+ar/1O0EuYzRpgMKrIoyB+nMeFKmdfsm7yg+2bGvdjk6LU[/tex]', '[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+arwEnjFR9plELZg0BgU0q743/h/QU26L5o6mPu0CtZVYh[/tex]', '[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+ar/1O0EuYzRpgMKrIoyB+nMeIfRnk5veKSajTUbxAMHCH[/tex]'], 'type': 102}
未知类型：{'options': ['[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+arxaBDEswO8q8DbNbDgMQOI3O9rqGkzl7Ga+CPFfZV3WQ[/tex]', '[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+ar/1O0EuYzRpgMKrIoyB+nMeFKmdfsm7yg+2bGvdjk6LU[/tex]', '[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+arwEnjFR9plELZg0BgU0q743/h/QU26L5o6mPu0CtZVYh[/tex]', '[tex=6.571x1.357]Oiw2NpXD3xAlC9jU+H+ar/1O0EuYzRpgMKrIoyB+nMeIfRnk5veKSajTUbxAMHCH[/tex]'], 'type': 102}
举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 假设“☆”是一种新的运算，若3☆2=3×4，6☆3=6×7×8，x☆4=840(x＞0)，那么x等于： A: 2 B: 3 C: 4 D: 5 E: 6 F: 7 G: 8 H: 9
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 【单选题】Which of the following matrices does not have the same determinant of matrix B: [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -1, 0, -9,-5] A. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 0; -1, 0, -9, -5] B. [1, 3, 0, 2; -2, -5, 7, 4; 1, 0, 9, 5; -1, 0, -9, -5] C. [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -3, -5, -2, -1] D. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 1; -1, 0, -9, -5]