• 2022-07-29
    已知三次Hermite插值多项式满足:H3(χ0)=f(χ0),H3(χ1)=f(χ1),H′3(χ0)=f′(χ0),H′3(χ1)=f′(χ1)。如果增加一节点χ及条件f(χ2),f′(χ2),试从H3(χ)构造五次多项式H5(χ)满足:H5(χi)=f(χi),H′5(χi)=f′(χi)(i=0,1,2)