$n=1$时，经典图像中电子围绕质子作半径为$a_0$的圆周运动时的总能量。(1) 总能量为：
A: $E=\dfrac{e^2}{8\pi \epsilon_0 a_0}$
B: $E=-\dfrac{e^2}{4\pi \epsilon_0 a_0}$
C: $E=\dfrac{e^2}{4\pi \epsilon_0 a_0}$
D: $E=-\dfrac{e^2}{8\pi \epsilon_0 a_0}$
A: $E=\dfrac{e^2}{8\pi \epsilon_0 a_0}$
B: $E=-\dfrac{e^2}{4\pi \epsilon_0 a_0}$
C: $E=\dfrac{e^2}{4\pi \epsilon_0 a_0}$
D: $E=-\dfrac{e^2}{8\pi \epsilon_0 a_0}$
举一反三
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