在区域编码算法中,设端点P1和P2的区域编码分别是code1和code2,若(),则P1和P2同下方、左方或右方。
A: code1=0且code2=0
B: code1&code2≠0
C: code1&code2=0
D: code1≠code2
A: code1=0且code2=0
B: code1&code2≠0
C: code1&code2=0
D: code1≠code2
举一反三
- 对于以下代码段：实现奇偶数的判断Code1:if number % 2 == 0:even = Trueelse:even = FalseCode2:even = number % 2== 0（）是正确的。 A: Code 1有错误 B: Code 2有错误 C: Code 1和Code 2都有错误 D: Code 1和Code 2都是正确的，但Code 2更好
- Analyze the following code: Code 1: int number = 45; bool even; if (number % 2 == 0) even = true; else even = false; Code 2: int number = 45; bool even = (number % 2 == 0); A: Code 1 has compile errors. B: Code 2 has compile errors. C: Both Code 1 and Code 2 have compile errors. D: Both Code 1 and Code 2 are correct, but Code 2 is better.
- RADIUS协议CODE＝1的应答包中，CODE值可以是（） A: 2 B: 4 C: 1 D: 3
- <strong>语句<code>printf("%d",1/3);</code>输出为<code>0.33。</code></strong>
- Use the following code to answer the following questions: int id = 0; cout [< "ID: "; cin ]> id; if (id == 1) cout << "Janet"; else if (id == 2 || id == 3) cout << "Mark"; else if (id == 4) cout << "Jerry"; else cout << "Sue"; (1) The above code display ____when the id variable contains the number 2? (2) The above code display ____when the id variable contains the number 4? (3) The above code display ____when the id variable contains the number 3? (4) The above code display ____when the id variable contains the number 8