• 2022-07-26
    高阶求导f^(10)((1+x)/(1-x)),即第十阶导数~
  • f(x)=(1+x)/(1-x)=(x-1+2)/(1-x)=-1+2/(1-x)f^(10)((1+x)/(1-x))=2*f^(10)(1/(1-x))=-2*10*1/(1-x)^10=-20*1/(1-x)^10

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      设函数f(x)具有二阶导数,g(x)=f(0)(1-x)+f(1)x,则在[0,1]上(  )

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      F(1/X)=X/1-X*X求f(x)=

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      17e0b849b7d64bd.jpg,计算[img=19x34]17e0ab14a855463.jpg[/img]实验命令为(). A: syms x;f=diff(asinsqrt(x))f=1/2/x^(1/2)/(1-x)^(1/2) B: f=diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2) C: syms x;diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2)

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      17da42840675a6d.jpg,计算[img=19x34]17da4275482315f.jpg[/img]实验命令为(). A: syms x;f=diff(asinsqrt(x))f=1/2/x^(1/2)/(1-x)^(1/2) B: f=diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2) C: syms x;diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2)

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      f(x)满足f(x/1)=x/(1-x^2),则f(x)=?