设某电子产品的寿命服从指数分布,其分布函数为[tex=13.643x3.357]ew/x16XKTeioZZ/K64Md10TQTtELQpDjrybQoQgbdZoJ0kEX4bzPVkEFhduG7MFURDbc9RNqiDHlb3HKZSSXQ8F7TdbzjmI4HsE1mbiWG1vfOS5rGnbtm4BNw9ZjpVv8HOHgT+4sHmeaUVJvvFr5XHvUwAKs5InSOkrT5U6xmS1VobTvyv42sH3t8xSUB4ro[/tex][tex=6.143x1.357]wmcCyupgcsjFVHtA2t0h4m3OfGocOSmlo9q+K1nIm+bM/otATqpNZU4qfcL5YhHJ[/tex]为测得[tex=0.643x0.786]SBMIs+VUk7//BOpfqlQl0w==[/tex]个产品的寿命,试求[tex=1.714x1.214]MZAvqdooCdl+icBINL+5CQ==[/tex]的矩估计.
举一反三
- 设某电子产品的寿命服从指数分布,其分布函数为[tex=13.643x3.357]ew/x16XKTeioZZ/K64Md10TQTtELQpDjrybQoQgbdZoJ0kEX4bzPVkEFhduG7MFURDbc9RNqiDHlb3HKZSSXQ8F7TdbzjmI4HsE1mbiWG1vfOS5rGnbtm4BNw9ZjpVv8HOHgT+4sHmeaUVJvvFr5XHvUwAKs5InSOkrT5U6xmS1VobTvyv42sH3t8xSUB4ro[/tex][tex=6.143x1.357]wmcCyupgcsjFVHtA2t0h4m3OfGocOSmlo9q+K1nIm+bM/otATqpNZU4qfcL5YhHJ[/tex]为测得[tex=0.643x0.786]SBMIs+VUk7//BOpfqlQl0w==[/tex]个产品的寿命,试求[tex=1.714x1.214]MZAvqdooCdl+icBINL+5CQ==[/tex]的MLE.
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 输出九九乘法表。 1 2 3 4 5 6 7 8 9 --------------------------------------------------------------------- 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=