设y’=2x,且x=1时,y=2,则y=()。
举一反三
- 如下程序的输出是什么? #include <stdio.h> void Swap (int x, int y);int main() { int x = 1; int y = 2; printf ("x=%d,y=%d\n", x, y); Swap (x, y); printf ("x=%d,y=%d", x, y); } void Swap (int x, int y) { int temp; temp = x; x = y; y = temp; printf ("x=%d,y=%d\n", x, y); }? x=1,y=2x=2,y=1x=2,y=1|x=1,y=2x=1,y=2x=2,y=1|x=1,y=2x=2,y=1x=1,y=2|x=1,y=2x=1,y=2x=1,y=2
- 如下程序的输出是什么? #include [stdio.h] void Swap (int x, int y); int main() { int x = 1; int y = 2; printf ("x=%d,y=%d\n", x, y); Swap (x, y); printf ("x=%d,y=%d", x, y); } void Swap (int x, int y) { int temp; temp = x; x = y; y = temp; printf ("x=%d,y=%d\n", x, y); } A: x=1,y=2x=2,y=1x=2,y=1 B: x=1,y=2x=1,y=2x=2,y=1 C: x=1,y=2x=2,y=1x=1,y=2 D: x=1,y=2x=1,y=2x=1,y=2
- 设\(z = u{e^v}\),\(u = {x^2} + {y^2}\),\(v = xy\),则\( { { \partial z} \over {\partial x}}=\) A: \({e^{xy}}({x^2}y + {y^3} + 2x)\) B: \({e^{xy}}({x}y^2 + {y^3} + 2x)\) C: \({e^{xy}}({x}y + {y^3} + 2x)\) D: \({e^{xy}}({x^2}y + {y^2} + 2x)\)
- 中国大学MOOC: 设X~N( 3, 2),Y~U( 2, 8),且X与Y相互独立,则D(2X–Y) =().
- 设X ~ N ( 3 , 2 ),Y ~ U ( 2 , 8 ),且X与Y相互独立,则D(2X – Y) =( ). A: 1 B: 5 C: 7 D: 11