求下列曲面所围区域的体积：[tex=11.0x1.429]+e5DouuO5t0uQO1NFFXpeFk+6jda9byklz52olfv41+MhDtQkpDIBCq4QVROd7pq[/tex]
解：[tex=13.857x2.857]M8Nlu5zwoUG3iOx+P1kHvw208hlU2Dh2BZNS7TKdv5PPgxBH1uYMzVMRvqyzJn0z+NxrUOytEUvFLRAoDeGoDLUzqNao2ggIlpCVUfCxa6QFdNQvqiF8n2Qe4V1G9bO+IMBgNccWr57kdcKVmJOYCg==[/tex]
举一反三
- 求下列曲面所围区域的体积：[tex=9.357x1.214]tC5WXgEjMTR/uC94hfLjIwEJsPqSCk5MjPtEWlUSBv8=[/tex]
- 求下列曲面所围区域的体积：[tex=21.214x1.571]U37dn8znznFebviy+cQNpoyhcq5kPDS0bLRwOCFj4NKGCpJtKUaxmAdNpfC1hH9w4AMlJMWjrfFqhtytbkm42lYfvBWHN/pdr2Z9JLuii/g=[/tex]
- 变换成极坐标，求下列曲面所围成的区域的体积：[tex=12.071x1.571]5/zDgG6yUox2lb72MEhNyI5VAXFrADv2aSLlIvfsHAAV/oK5RY2LXeEU7nrwAEBsnts30HNNYd/xAkNnfoGHATKAWDlg7HqhI4Rh1jp5gXM=[/tex]
- 求下列曲面所围立体的体积：曲面[tex=5.214x1.429]eO+GzgNDaVFWKGy64CHSRfMASoJS+SMcA02cQOGdVs0=[/tex]，[tex=5.429x1.643]om0DX395gcXIzo/bROmkufWtqMtpIGjOXanzOoSlTUY=[/tex].
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
内容
- 0
set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 1
求下列曲面所围立体的体积：[tex=4.429x1.143]gGaSB0H7dT9N9/wJvrnk6A==[/tex]，[tex=4.643x1.429]MlIOqqYu5u1ffsbpFjlv5qsy4u6w8nSJ8jo5fVayDOs=[/tex]，[tex=6.571x1.571]R4SVfNVkSCVv5DUz4Y17qjFAGt5Q826lN7ia5jqx2qs=[/tex].
- 2
计算下列曲面围成的立体的体积：[tex=11.0x1.429]pZ8sm+BLKJ2Z+k4jnd5lFhzpB0CBSoh++7ePMhOyNi3fzMJDNGAPAklthgyfQsLI[/tex].
- 3
【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 4
求由曲面[tex=13.643x1.429]4CLkxHqXndfwc/JP+ksZltizC44D02kTRT7aQJrzSuySgd6X3cshBlmi/Hud25ux[/tex]所围立体的体积.