求下列曲面所围区域的体积：[tex=21.214x1.571]U37dn8znznFebviy+cQNpoyhcq5kPDS0bLRwOCFj4NKGCpJtKUaxmAdNpfC1hH9w4AMlJMWjrfFqhtytbkm42lYfvBWHN/pdr2Z9JLuii/g=[/tex]

2022-06-29

求下列曲面所围区域的体积：[tex=21.214x1.571]U37dn8znznFebviy+cQNpoyhcq5kPDS0bLRwOCFj4NKGCpJtKUaxmAdNpfC1hH9w4AMlJMWjrfFqhtytbkm42lYfvBWHN/pdr2Z9JLuii/g=[/tex]

答案：

解 [tex=29.714x6.357]a0s3MH7cLIdmiBRR0YN069n4Bn+We5mxzKVAJvltO5u5nFaJFgTGHS7CZYYVrMX7ZjYAUDmBxsEGRjj+/ELWBV5TIZQ6yH3ZU+uBsD0v3oKuisECoInEBv5vC06C4tBAAQsFkzlon/tq7ZCa1xPqLyowguP4jEgDjUUiJh/GU8UqySVda6KsPHwnaAz+yfb3uo1Qk8FGa9WsmWZgyUiRaCvcBy7KpbP4B6TMAuxAgKa2c3l6KwC5HAUcdUr5G09aMFbgfotr1pNIBU0zQLTU9KhbVsPFoO4dZnBRsKXNGz80IfpjWb0LF0dS8DYvLbthyWGYJQxo0XlDzTTuNj1u2n1Fzh/rcJuGaeIyQmhYK5TQ1Xuux3erpS2dc3sYnbGrbJkl8K2teums7RnxGm4JXMvJGrUm+uP4Z/iAEfFsJplvr7iatwyX/0QcPefZ4f8W2DHExly2Dw4QjnPNVrTfvHIshHgt3/68cV+P0hrmC1R++8HGG1/9f04n22ZdSqg1[/tex]

举一反三

内容

0
输出九九乘法表。 1 2 3 4 5 6 7 8 9 --------------------------------------------------------------------- 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
1
>>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
2
set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
3
由曲面\( z = {x^2} + {y^2} \) ，\( {x^2} + {y^2} = 4 \) 和\( xOy \) 平面所围立体体积为（） A: \( 6\pi \) B: \( 7\pi \) C: \( 8\pi \) D: \( 9\pi \)
4
求下列曲面所围立体的体积：曲面[tex=5.214x1.429]eO+GzgNDaVFWKGy64CHSRfMASoJS+SMcA02cQOGdVs0=[/tex]，[tex=5.429x1.643]om0DX395gcXIzo/bROmkufWtqMtpIGjOXanzOoSlTUY=[/tex].