cos(πx/2)与(π/2)(1-x)是等价无穷小?(x趋于1)
举一反三
- 为什么当x趋于0时,(1+x^2)^1/3-1与1/3x^2是等价无穷小?
- 17e0b849d3a4a3b.jpg,计算[img=19x34]17e0ab14a855463.jpg[/img]的实验命令为( ). A: syms x; f=diff((1+sin(x)^2)/cos(x),1)f=2*sin(x) + (sin(x)*(sin(x)^2 + 1))/cos(x)^2 B: f=diff((1+sinx^2)/cosx,1)f=1/2/x^(1/2)/(1-x)^(1/2) C: syms x;f=diff((1+sinx^2)/cosx,1)f=2*sin(x) + (sin(x)*(sin(x)^2 + 1))/cos(x)^2
- limxx趋于负无穷(1-x)^(1/x)
- 求函数[img=107x38]17da6537b12a2e0.png[/img]的导数; ( ) A: 2*x*sin(1/x) - sin(1/x) B: 2xsin(1/x) - cos(1/x) C: 2*x*sin(1/x) - cos(1/x) D: 2*x*cos(1/x) - cos(1/x)
- x趋于零(1+ax^2)^1/3-1和cosx-1是等价无穷小求a的值.