设函数[tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex]连续. 则在下列变上限积分定义的函数中，必为偶函数的是
未知类型：{'options': ['[tex=8.5x2.643]yM+KA5UMjZ+V8rBufYdg52cdbfwJBNZ65kKkDSpaWBkcCoXXLITnTN17QT6O7wfW[/tex]', '[tex=8.5x2.643]yM+KA5UMjZ+V8rBufYdg56J2GjSxhQ3JPvtpO39THkDKtAt2jpK4fbf6TZCvsAH3[/tex]', '[tex=5.214x2.643]vVNrdpwvJZ6ALXLCp26UwlfcaRyBywp5+Wd3ZZtY9ydRqu6WGqqF7nkN5BViLU+m[/tex]', '[tex=4.857x2.643]lDwjF/bS0+jAhiOYIK0+dwId2m42D0mZUA0T9XoduvE=[/tex]'], 'type': 102}
未知类型：{'options': ['[tex=8.5x2.643]yM+KA5UMjZ+V8rBufYdg52cdbfwJBNZ65kKkDSpaWBkcCoXXLITnTN17QT6O7wfW[/tex]', '[tex=8.5x2.643]yM+KA5UMjZ+V8rBufYdg56J2GjSxhQ3JPvtpO39THkDKtAt2jpK4fbf6TZCvsAH3[/tex]', '[tex=5.214x2.643]vVNrdpwvJZ6ALXLCp26UwlfcaRyBywp5+Wd3ZZtY9ydRqu6WGqqF7nkN5BViLU+m[/tex]', '[tex=4.857x2.643]lDwjF/bS0+jAhiOYIK0+dwId2m42D0mZUA0T9XoduvE=[/tex]'], 'type': 102}
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- [tex=1.857x1.0]1FVfIOJf7ISeQGf+8HT7Iw==[/tex]尿素的合成需消耗[tex=2.214x1.286]iLZ8dFzDhyDszs4Q6Iairw==[/tex]摩尔数是 未知类型：{'options': ['2', '3', '4', '5', '6'], 'type': 102}
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 下列函数是哪些函数复合而成的？（1）[tex=4.214x1.286]6PuLCl/TwscTl61WSePGog==[/tex]；（2）[tex=5.214x1.286]+mZ2Cm2OprRKGTGg0iqmyZx+4lZ796PxrSQNx30R9UU=[/tex]；（3）[tex=4.214x1.357]jTbrMH55vzOFOJlLSnfh103OHFmRhIjXZGzPnfweOX0=[/tex]；（4）[tex=6.071x1.286]W2A0mViHY0pK74wEByr6ED5K+AKV/pxHaeQdYGQBxwc=[/tex]；（5）[tex=6.714x1.429]8up/G1s+GteD9ejcGkFVmYl3TTtTik5kuwrPDCv0JkbGIWyY33cnaw7XtBiPcSnh[/tex]；（6）[tex=5.714x1.286]APaFs2rWyubdkzLcUVVxVJSSAsLEOtXn4KjnToE2BQA=[/tex]；