题图所示的为一个 5 节点网络,已知各支路阻抗标幻值及节点编号顺序,要求(1)形成节点导纳矩阵[tex=0.643x1.0]O+viFNA0oHTwnBtQyi80Zw==[/tex];(2)对[tex=0.643x1.0]O+viFNA0oHTwnBtQyi80Zw==[/tex]矩阵进行[tex=2.214x1.0]S+jhS6fHZt4BbUVRRCB0Nw==[/tex]分解;(3)计算与节点 4 对应的一列阻抗矩阵元素。
(1)形成节点导纳矩阵[tex=22.929x9.5]Ck4j1YFlvVH5wCAykOEMi/2f5PxQ445UkiZU0tBsHJWB6/XiU8D1bmm+gZh/DFT6It5XOY4L0BPvYdbQFX6vYL6qvfw5MeFv0KNgVYnxEo9GzoyOonqYJ5r+05e3+EEeDkClZrwW8rnAOtiCCNa+sIrMHoxfEa/pICo7ATJD+9nwgJiuxNfNNslyWJq/T0Ll0KDnhE/GNaLqOAE6hPNmhNldfA2v4xA+PvFhpovHFvMHTPweGmHMwtmy1cUnxH3rfW4UPzbX3r+N2TM85Yf10bZXlzhb3f9zI8E39TcnKdRo4WGh4F/pkyvphxIzrIFlyHJfyOrzucvM/NYG5qJGnkXGK4k88vAk18XvrhRHDLqbyAfMn/Fbanl50AFAlMNCQh6dJuI6bnn5SB5/H02J0LlBeGdriKw4ONGokwOZ94E=[/tex][tex=25.071x10.786]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[/tex]于是可得节点导纳矩阵[tex=29.214x6.643]8Nqiw9Ks5F1BHYqRKfk38nP3mmVm8NdOLYd3v0NKY/kWf8/BXZGiYy8z7g1pLgOkY9eQb9hyQVqSJuCQHgDLZBz7fl+wqfQYkO7jUFTGHNiPLQWEEzTGVlo6AWluwxrRGifzl5tMDrNxrGOy8wZvXylliYhrPRtkW5T9YjVXdwotekMUj+yfGKjVSp25eTDGt8tm0u/ytvLM88OfwW6fYdvS05LwiGLDltle//8VyGQur1uGGF6gCmjzBJs9Qf5uylN2wvE7v8XR6LKYtRFx1jG19eDnOs/H5L+ZZ1s5IMKrhTXO/isoz+22AVrvYdUyU14iMXzMrirxOshkRhR8eDWMOCf6NxSwruyWWFjzekGO0itoLB6iqy3bZ5SvHvZTX4u7ARgldJ6HgmDD5f0qOe3qOeZnYi8zjJyZyade551IQHgWi5iQg6fyeeB8Ro2W[/tex](2)对[tex=0.643x1.0]O+viFNA0oHTwnBtQyi80Zw==[/tex]矩阵进行[tex=2.214x1.0]S+jhS6fHZt4BbUVRRCB0Nw==[/tex]分解[tex=19.643x8.643]Ck4j1YFlvVH5wCAykOEMiy7p2TfYfDRhWawz2XbppUtJdY8wHjFON+m56n8mQOkP4LIA17PQdbxbqk1c/+rm6UtvtY7pxQ1C4J0FbcEYy9sv6ROlq1aSAyLwAMAmYzUkaXj+DkjhBAEyfozkDrtRhwv8EuRept2BbSP8zCIxTNKPbymWaLGAgNt3hg/imMPGGXN0eTuv8+PnbrFV/zLu43uom3DmQNuLPqBWqW6PVUTdyLyvBe65hvo3h2rvQyG3az3e1vHi9+ZPHylkBQ7m32XTOv71DEOE2vFMb3OyaO7hAbjXVI4Ol3RoD6lPqbxV3DfYsBMzWnOuA1WFAMr79fzYa4hwd/vSuDdOwU4P4GwqJ8d1f5LikAcUiabHdD9QscJ2zq26DwuLuMzPWXeNidqmPB2wtNsWunka58HYynWEtEp30LQjSCfHMAt/X+A4numm5ZwP9lvKpKnWTDujFQ==[/tex][tex=26.5x16.286]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[/tex][tex=25.071x4.357]a0s3MH7cLIdmiBRR0YN06+vkGDnRVdpyBwRvQLV/0V+Wv0LoNkkKBizl3ieoGnI894/ZqR9Mxo2zYfqK3zUrLNRwFhMqKFuOYwL1J0O43owKS475aY2fvgjE/F+5S+4ga7j6WjEpXH2ddf9XMTvLKOOomI0dSajw0BKo8Io3CFNEV/iIwJQgqHs//Ekv8/xvvxCTsS5er62tfnnEgX+XPauUiFuhmAlcE1mha/gnSnAYXsplvN76QfEw99XEbB0EosSWxbTM6HVOZyoM2JfMdQ==[/tex][tex=18.5x6.214]a0s3MH7cLIdmiBRR0YN06wBNmu5WY2dNDae0ew0Gg+OvkQxD8i8V4al9RrwRyumiy/ouaXbAovln27W5aChdEXrrgwp12nVeCYnvQ6PPUeggJfXEn4W7leJYfRJmWxa2l53HmOIRsV5CuXrjG7ldQYsj2LMwM0KS25eizVg/YBThhqrRsfaB1PJWBllq+bIbdsVRuGQJLxBZjsY+m9JcFX7a4jH1s6cMJAlD/hZ7LMeucks+Ipm7VLp+PdheIChbFWFSfcc395G+EgZlQj1pYV5bKJcpHhDk4+KCcSRAOdiIp11wc8ao0wL8UXnLJ9jpjdv9JaxsGYA75KLgnguk1w==[/tex]于是得到因子表如下,其中下三角部分因子存 [tex=3.786x1.571]QI9qONtikEBmJEDkIrRPbDMkHpSPU2usePtuQo6nZXg=[/tex],对角线存[tex=0.857x1.0]PvQ1rNj9zmhWbdNmDhnQhA==[/tex],上三角部分因子存[tex=0.714x1.0]VkfVn2nqVgRpP58Qb+BUWQ==[/tex]。[tex=25.429x7.214]8isLcl5+n7A+yUi18ZJNJGAP8xZS5wp7wEQTQLp4Ag/GViel77m53Zmi+b7nD5XaeLFZtacOGvakZuJPU8DIbUvm9+6JKvD7NaVL0zyxK9cLqx8nfTNZwpnE19ZgCoEmtuO262X5vsJS53z6LP3O3vJQ+gVxG3ySo6a2f2MoMoRkeliwv9e5u6+CgIt7R8UG5xPKoiqxJyTT04pYg6f6lPgzmjSRV70nryMEa4ErQ9wAOXg/ilOwi4qeBVQyJ0IJGnkgC7WIcKc2XK6i+bmCQCoKO30G68g857wi+CPziiil/NZ/B5I8LEqWmaJDqPv3tYUq35Le/KPDy7OcBGfX09kHtjad6Pd09f1YtPn0csjAPVL+Zc2BflLi8l01teyT8SHK989PgXtbTMcGheOeaiyZkzYBAu4KSNiPrN/wmi4=[/tex](3)利用因子表计算阻抗矩阵第[tex=0.429x1.214]rmIPPJrP+tFN2kAYPlU/4g==[/tex]列元素,需求解方程[tex=4.714x1.286]FtyXZZurA1v/6WjDd845QRP5DiTARzaqx4R/0/g37bU=[/tex]这个方程可以分解为三个方程组[tex=9.786x1.286]onPqF2kXMbbCeYF9BnpBnjaaNK3qKSwZEZM+X23LFCFR5y3XCAwacibZ9W/NplwZ[/tex]令[tex=1.714x1.214]8EJ5X3VtK4t9Nwsxv7je2A==[/tex],利用教材上册式(4-35)~式(4-37)可以算出[tex=23.0x5.929]Ck4j1YFlvVH5wCAykOEMi06EsSxKAW2IYvevt41NVSS1iRy8RNl0Ex1Ox+DxwPzkiqUDQFXXaEo5sYekfRxWDQiBfKiMIUnH6LEmjElsOdi8d/4p23VIVcs1ZafIms7aQt8iPnyO3W4rZ55nRjB3uHWP55DrQCK6gVoC2RhqpIfwNQI32rJ/LqXUhIIn+CRQ6fj5o+8NTf9t/+I7l8f7cOgjlPCFYzW1fosty94B+T6vwDypmx5KhOdu95JPfdsBtCRfmr/TiLBYNOUfFixG/jFa4QWEseUMKbJPiOfOG0y+Xth8If//0UB4QNl/6Tg8G73yqahig5V15iJUrJAum9tpEBDveIrj7r/o/4Udqviiv5AxEaDGr91xZxu8c7F1[/tex][tex=27.5x9.929]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[/tex]同样可以算出其他各列的元素,结果如下[tex=23.929x6.643]m7A5mOGR8lpC8FklKWSys1GJNeKTzl02JbBAEAY4vY10gcrwRNAepGtdRhEBODN5Q8XhEbIfjOnps+/63nkk48McZ/ClhrLIwseegk2DVd3a2ptnDKVdM21UDEZ8e5kOJTwJwbn1xxbJaSyLre9eioWh8mdTTtS0EboqsPuMuQsZuKFYJbhDQ+8Pt5eHPOODEXE9lMeR48TjJpM2CFkouNVQqyQvdQK5UEn1O9VmujWgNlDlmjOBr7G2ha6dNGPqigccbp7YU8bkvQk7FZFWcqt9jvUQhEjDrAdbKlNdqQb3UnlF4UjXtxh2zffulCLYKYLUir8ZU9EKBSpT7KqBHFG6UuE8M3luxcdqjrrXo7O0g4piTIoo84MZNBjFwOdX9tplEzHzpE5yNNMT3wd0GplbeZqEq2mix6ipSOmtj3rooa/Ui6rebgZUHLwYizGp[/tex]
举一反三
- 3 节点网络如题图所示,各支路阻抗标幺值已在图中注明。试根据节点导纳矩阵和节点阻抗矩阵元素的物理意义计算各矩阵元素。[img=903x231]1797d488ae37669.png[/img]
- 如题图所示,已知某网络的零序节点导纳矩阵,网络中[tex=1.0x1.0]G+ERgoWRxeowbOaR7/sBZg==[/tex]支路和[tex=0.929x0.786]PHHwzEEc9MQeRjEhhMtZVw==[/tex]支路之间存在互感,试就下列情况修改节点导纳矩阵:[tex=1.0x1.0]G+ERgoWRxeowbOaR7/sBZg==[/tex]支路两端断开。[img=691x682]179bb5c29ec4efc.png[/img]
- 如题图所示,已知某网络的零序节点导纳矩阵,网络中[tex=1.0x1.0]G+ERgoWRxeowbOaR7/sBZg==[/tex]支路和[tex=0.929x0.786]PHHwzEEc9MQeRjEhhMtZVw==[/tex]支路之间存在互感,试就下列情况修改节点导纳矩阵:[tex=1.0x1.0]G+ERgoWRxeowbOaR7/sBZg==[/tex]支路两端断开并挂地线进行检修。[img=691x682]179bb5c29ec4efc.png[/img]
- 如果已知某一电力网有6个独立节点，其中1个平衡节点,3个[tex=1.5x1.214]Ig/HKDLaw2zBNzQyXE+OwA==[/tex]节点，2个[tex=1.286x1.0]ja2MJefKzsGJN85Jp5n2Tg==[/tex]节点,则以下说法不正确的是（ )。 未知类型：{'options': ['其导纳矩阵为6阶。', '其[tex=1.071x1.143]qU1DX3LoO41cf4YxDgAF0A==[/tex]矩阵为5阶。', '其[tex=1.286x1.143]8AmaS7lYKavIUYWL6CgqRJ7Atlo2w2jMgxcp8AOvbqg=[/tex]矩阵为3阶。', '其雅可比矩阵为6阶。'], 'type': 102}
- 设二维离散随机变量[tex=2.5x1.357]PWg5V4GQQafckGNgbx6gmw==[/tex]的可能值为(0, 0)，(−1, 1)，(−1, 2)，(1, 0)，且取这些值的概率依次为1/6, 1/3, 1/12, 5/12，试求[tex=0.857x1.0]N7iCrOsS+NNEUUlnsYCi1g==[/tex]与[tex=0.643x1.0]O+viFNA0oHTwnBtQyi80Zw==[/tex] 各自的边际分布列．
内容
- 0
获得系统节点阻抗矩阵的方法有（）。 A: 根据电力系统等值网络用支路追加法直接形成 B: 用节点导纳矩阵求节点阻抗矩阵 C: 用支路导纳矩阵求节点阻抗矩阵 D: 用支路阻抗矩阵求节点阻抗矩阵
- 1
求题[tex=2.786x1.143]e+E8dT4vv67mOIV/Ng7Itw==[/tex]图所示双[tex=0.643x1.0]awBC2UvU2WxG45VihksPuw==[/tex]电路的[tex=0.643x1.0]O+viFNA0oHTwnBtQyi80Zw==[/tex]参数矩阵。[img=336x202]179cf9c7d0d316f.png[/img]
- 2
电力系统等值电路如题图所示,支路阻抗的标幺值已注明图中。[img=1096x244]1797f96a4f931f7.png[/img]形成节点导纳矩阵(或节点阻抗矩阵),并用以计算节点 3 的三相短路电流。
- 3
给定[tex=3.571x1.357]0jgNZNb5KE0SpRQgBt7oQg==[/tex]，设x=0是4重插值节点，x=1是单重插值节点试求相应的Hermite插值公式，并估计误差[tex=4.071x1.357]ZHsKcW72rLaSaexOsDovRw==[/tex]
- 4
导纳矩阵的中节点[tex=0.357x1.0]+eJLelx8thmbkEj/Y0iCOw==[/tex]的自导纳等于( )。